Answer:
Distance of closest approach, 
Explanation:
It is given that,
Charge on proton, 
Charge on alpha particle, 
Mass of proton, 
Mass of alpha particle, 
The distance of closest approach for two charged particle is given by :



So, their distance of closest approach, as measured between their centers
. Hence, this is the required solution.
Answer:
c = 1 / √(ε₀*μ₀)
Explanation:
The speed of the electromagnetic wave in free space is given in terms of the permeability and the permittivity of free space by
c = 1 / √(ε₀*μ₀)
where the permeability of free space (μ₀) is a physical constant used often in electromagnetism and ε₀ is the permittivity of free space (a physical constant).
P = density × gravity acceleration × height
P = 1200 × 9.81 × 15/100
P = 1765.8
Answer:
<u></u>
- <u>See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.</u>
Explanation:
The <em>curved mirror</em> shown is a converging lens.
<em>To find the location and size of the image</em> formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (<em>Ray 1</em> in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.
The attached figure shows this ray in blue.
The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).