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pashok25 [27]
3 years ago
8

List 3 indicators that a chemical reaction has occurred.

Physics
1 answer:
mina [271]3 years ago
8 0
Hello! There are many indicators to show a sign that a chemical reaction has occured. These are 3 as followed.

1. An odor is produced.

2. A change in temperature.

3. A color change.

Others can be a formation of a solid or a gas.
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A train is moving with a velocity of 70 km/h. If north is taken as the positive direction, what is the direction of movement of
Anna11 [10]

Answer:

+70 km/h north

Explanation:

4 0
2 years ago
planet a takes one year to go around the sun at a distance of one au. .planet b is three a u. from the sun. how many years does
shtirl [24]

Answer:

3 years

Explanation:

Find the circumference of each orbit in AU.

2xπx1=6.283185307

2xπx3=18.84955592

Divide them.

18.84955592/6.283185307=3

3 years

4 0
3 years ago
Suppose you are an astronaut and you have been stationed on a distant planet. You would like to find the acceleration due to the
Maksim231197 [3]

Answer:

<h3> 1.40625m/s²</h3>

Explanation:

Using the equation of motion expressed as v = u+gt where;

v is the  final velocity of the ball

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

Given

u = 9m/s

v = 0m/s

t = 6.4s

Required

acceleration due to gravity g

Since the rock is thrown up, g will be a negative value.

v = u+(-g)t

0 = 9-6.4g

-9 = -6.4g

6.4g = 9

divide both sides by 6.4

6.4g/6.4 = 9/6.4

g = 1.40625m/s²

Hence the acceleration due to gravity on the planet is  1.40625m/s²

6 0
3 years ago
A positive charge +q1 is located to the left of a negative charge -q2. On a line passing through the two charges, there are two
AfilCa [17]

Answer:

please the answer below

Explanation:

(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is

V_1=k\frac{q_1}{r-1.0}-k\frac{q_2}{1.0}=0\\\\V_2=k\frac{q_1}{r+5.2}-k\frac{q_2}{5.2}=0\\\\

k=8.89*10^9

For both cases we have

k\frac{q_1}{r-1.0}=k\frac{q_2}{1.0}\\\\q_1(1.0)=q_2(r-1.0)\\\\r=\frac{q_1+q_2}{q_2}\\\\k\frac{q_1}{r+5.2}=k\frac{q_2}{5.2}\\\\q_1(5.2)=q_2(r+5.2)\\\\r=\frac{5.2q_1-5.2q_2}{q_2}

(b) by replacing this values of r in the expression for V we obtain

k\frac{q_1}{\frac{5.2(q_1-q_2)}{q_2}+5.2}=k\frac{q_2}{5.2}\\\\\frac{q_1}{q_2}=\frac{(q_1-q_2)}{q_2}-1.0=\frac{q_1-q_2-q_2}{q_2}=\frac{q_1-2q_2}{q_2}

hope this helps!!

3 0
3 years ago
Read 2 more answers
PLEASE I NEED THIS NOW ITS EASY I JUST DIDNT STUDY
dem82 [27]

Answer:

Explanation:

Frequency*speed

= 0.5*2.5

= 1.25m

3 0
2 years ago
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