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Agata [3.3K]
2 years ago
14

Calculate The pressure produced by a force of 392 N acting on an area of 8.0 m^2

Physics
1 answer:
Nonamiya [84]2 years ago
5 0

Answer:

Explanation:

500-0.05=499.95

500-100+5=405

100+100=10000

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Answer:

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Explanation:

We are given that

\theta=35^{\circ}

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v_x=v_0cos\theta=v_0cos35

v_y=v_0sin\theta=v_0sin35

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t=\frac{30}{v_0cos35}

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1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2

1.8=30tan35-\frac{6574.6}{v^2_0}

\frac{6574.6}{v^2_0}=21-1.8=19.2

v^2_0=\frac{6574.6}{19.2}

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Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=\frac{30}{18.5cos35}

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

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