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Shalnov [3]
3 years ago
13

The highest occupiable floor of any building is in the Sears Tower in Chicago. The elevators of the central tower of the buildin

g lift passengers 436.0 m above street level. If a continuous forces of 22310 N is exerted on one of these elevator cars as it travels from the ground to the top floor, how much work is done on the elevator car by the elevator's lifting mechanism?
Physics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

9727160J

Explanation:

Given parameters:

Height of elevator rise  = 436m

Force exerted  = 22310N

Unknown:

Work done by the elevator lifting mechanism = ?

Solution:

The work done by a body is the force applied to move a body in a specific direction;

          Work done  = force x distance moved

In this case, the force and distance moved is provided already;

        Work done  = 22310 x 436  = 9727160J

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Answer:0.1759 v

Explanation:

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I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

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3 years ago
An emf of 28.0 mV is induced in a 501 turn coil when the current is changing at a rate of 12.0 A/s. What is the magnetic flux th
dmitriy555 [2]

Answer:

Φ = 5.589×10⁻⁵  Wb

Explanation:

The inductance of a coil is given as

L = e/(di/dt) ..................... Equation 1

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Also,

The inductance of each turn of the coil when a magnetic field is step up in the coil  is

L = NΦ/i ................. Equation 2

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equating equation 1 and equation 2

e/(di/dt) = NΦ/i

making Φ the subject of the equation,

Φ = (e×i)/N.(di/dt) .................. Equation 3

Given: e = 28.0 mV = 0.028 V, N = 501 turns, di/dt = 12.0 A/s, i = 4.00 a

Substitute into equation 3,

Φ = (0.028×4)/(12×501)

Φ = 0.112/2004

Φ = 5.589×10⁻⁵ Weber

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Norma-Jean [14]

Answer:

Part a)

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Part b)

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Explanation:

Part a)

As we know that frequency = 1 MHz

speed of electromagnetic wave is same as speed of light

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P = \frac{I}{c} = \frac{9.68\times 10^{-3}}{3\times 10^8}

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no. the race care is at a constant speed. its staying the same speed.

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Furkat [3]

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