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serg [7]
1 year ago
13

A light ray in air enters and passes through a block of glass. What can be stated with regard to its speed after it emerges from

the block?.
Physics
1 answer:
Furkat [3]1 year ago
3 0

A light ray in air enters and passes through a block of glass , the speed will remain same after it emerges from the block

When a light ray enters into the glass then the speed of the light will get decreased because as a light ray enters into a denser medium , the speed of light get decreased . But when the light ray emerges out from glass , it going from denser to rarer medium , due to which speed will increase and come to same value as it was while entering the glass .

To learn more about denser medium here :

brainly.com/question/13613040

#SPJ4

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A car of the future requires 15kW of power to travel along a level road at 65km/h. A physics student wishes to use the car to dr
Luda [366]
Power = Energy / time, The time is the one it takes to cover 25 km at 65 km/h, so:  time = 25/65*60*60 = 1384.6 seconds.

Now the total energy needed for that is: Energy = Power * time = 15,000 * 1384.6 = 20769239.8 J.

The heat provides those J. The heat for a difference in temperature is:

Heat = mass * c_h * Difference_of_temperature,

Heat = 350 * 9,800 * (T-15)*0.88,

where the 0.88 is because some of the heat is lost, efficiency 88%. Now, you can equal both results and get T:

350*9,800*0.88*(T-15) = 20769239.8

T-15 = 6.88, and T = 21.88 C

The answer is T= 21.88 C

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7 0
3 years ago
Tres autos parten de un mismo punto con un intervalo de 1s, con velocidades "3V", "5V" y "Vx", respectivamente hacia un punto "p
kkurt [141]

Answer:

Vx = 15V

Explanation:

To find the speed of the third car you take into account that the distance that they travel is the same. Only time is different in one second. Mathematically you have:

x=3vt\ \ \ \ \ (1)\\\\x=5v(t-1)\ \ \ \ (2)\\\\x=v_x(t-2)\ \ \ \ (3)

you equal the first and second equation obtain the time t:

3vt=5v(t-1)\\\\3t=5(t-1)\\\\3t=5t-5\\\\t=\frac{5}{2}s=2.5s

then, you can equal the third and first equation:

3vt=v_x(t-2)\\\\3(2.5s)v=(2.5s-2s)v_x\\\\7.5v=0.5v_x\\\\v_x=15v

hence, Vx = 15V

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TRANSLATION:

Para encontrar la velocidad del tercer automóvil, tenga en cuenta que la distancia que recorren es la misma. Solo el tiempo es diferente en un segundo. Matemáticamente tienes:

iguala la primera y segunda ecuación obtiene el tiempo t:

entonces, puedes igualar la tercera y primera ecuación:

por lo tanto, Vx = 15V

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