Answer:
3.18 m/s
Explanation:
Given that
Initial speed of the ball, u = 20 m/s
Angle of inclination, θ = 45°
Distance from the ball, h = 50 m
Using equations of projectile to solve this, we have
We start by finding the time of flight, T
T = 2Usinθ/g
T = (2 * 20 * sin45)/9.8
T = (40 * 0.7071) / 9.8
T = 28.284/9.8
T = 2.89 s
Next we find the Range, R
R = u²sin2θ/g
R = (20² * sin 90) / 9.8
R = (400 * 1) / 9.8
R = 400/9.8 = 40.82 m
Distance the gk must cover
40.82 - 50 m
-9.18 m or 9.18 m in the opposite direction.
Speed of the GK = d/t
9.18 / 2.89 = 3.18 m/s
Net convective heat transfer loss rate (gnet)
Gnet = 2h, A (Ts - T∞)
=2(4.51) (0.001) (25)
Gnet = 0.2250 W.
There are two types of convection: natural convection and forced convection. Natural convection is caused by differences in the density of liquids due to differences in temperature (eg "hot air rises"). Global atmospheric circulation and local weather phenomena (including wind) are due to convective heat transfer.
Newton's Law of Cooling is a widely used equation for calculating both forced and natural net convective. The formula for Newton's Law of Cooling is Q = h A ΔT. Equation parameters and their typical US and SI.
Learn more about Net convective at
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Answer:
Explanation:
r = Distance between the charges
k = Coulomb constant = 
Net force is given by
The force on the particle 
is .
Answer:
Torque = 0.25Nm
Explanation:
To calculate the magnitude of torque, first we must calculate the lever arm. The lever arm is perpendicular distance from the axis of rotation to the line of the action of the force.
Lever arm = r sin theta
Where r = 4.9cm= 0.049m
Theta = 30°
Lever arm = 0.049 sin30° = 0.245m
Magnitude of torque = rfsintheta
f = 1.0T
Magnitude of torque= 0.245×1.0 = 0.245Nm
To 2 significant figure=0.25Nm
