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katovenus [111]
1 year ago
14

if the current through a resistor is increased by a factor of 4, how does this affect the power dissipated?

Physics
1 answer:
lbvjy [14]1 year ago
4 0

The new current will be 4I. The power dissipated by the resistor will increase by a factor of 16.

<h3>What is a resistor?</h3>
  • Using electrical resistance as a circuit element, a resistor is a passive electrical component with two terminals. In electrical circuits, resistors are used, among other things, to limit current flow, modify signal levels, divide voltages, bias active devices, and terminate transmission lines.
  • As test loads for generators, power distribution systems, and motor controls, high-power resistors that can create many watts of heat rather than just electrical energy can be used.
  • Variable resistors can be used as sensors for force, heat, light, humidity, humidity, and chemical activity or for adjusting circuit components.
  • Electrical networks and electronic circuits frequently contain resistors, which are found everywhere in electronic equipment. Practical resistors are discrete components that come in a wide range of materials and forms.

To learn more about resistor refer :

brainly.com/question/24858512

#SPJ4

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A pendulum bob is given velocity u =
Mama L [17]

Answer:

V = P = 0 m/s

Explanation:

When a pendulum bob is given an initial displacement or the initial velocity, it starts to execute periodic motion or simple harmonic motion. During this motion the kinetic and potential energy keeps interconverting. The kinetic energy becomes maximum at the lowest point, that is the mean point. Hence, the velocity is maximum at this point, as well. Similarly, at both extreme positions the potential energy becomes maximum due to maximum height, while the kinetic energy becomes zero at the highest point, that is extreme positions. At these, positions the velocity will be minimum and it will be zero due to zero kinetic energy. Hence, at both extreme positions the bob stops momentarily before, reversing the direction. Hence,

<u>V = P = 0 m/s</u>

7 0
3 years ago
How does a shovel make work easier for digging a hole?
bezimeni [28]
It makes it easier to dig a hole because it helps pick up dirt
4 0
3 years ago
Read 2 more answers
Saturated water vapor at 200 kPa is condensed into a saturated liquid via a constant-pressure process inside of a piston-cylinde
evablogger [386]

Answer:

The process is not possible

Explanation:

if we want to determine if the process is possible , we can check with the second law of thermodynamics

ΔS≥ ∫dQ/T

for a constant temperature process ( condensation)

ΔS≥ 1/T ∫dQ

and from the first law of thermodynamics

ΔH = Q - ∫VdP , but P=constant → dP=0 → ∫VdP=0

Q=ΔH

then

ΔS≥ΔH/T

from steam tables

at P= constant = 200 Kpa → T= 120°C = 393 K

at P= constant → H vapor = 2201.5 kJ/kg ,  H liquid = 1.5302 kJ/kg

, S vapor= 7.1269 kJ/kg , S liquid 1.7022 kJ/kg

therefore

ΔH = H vapor - H liquid = 2201.5 kJ/kg -  1.5302 kJ/kg = 2199.9698 kJ/kg

ΔS = S vapor - S liquid = 7.1269 kJ/kg - 1.7022 kJ/kg = 5.4247 kJ/kg

therefore since

ΔS required  = ΔH/T = 2199.9698 kJ/kg/(393 K)= 5.597 kJ/kg K

and

ΔS= 5.4247 kJ/kg  ≤ ΔS required=5.597 kJ/kg K

the process is not possible

5 0
3 years ago
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
Olenka [21]

Answer:

1.3m/s²

Explanation:

Given values in the first part: acceleration a, time t₁:

1) velocity v₀ = at_1

2) height h₀ =\frac{1}{2}at_1^2

Given values in the second part: acceleration -g,  time t₂:

3) height h = -\frac{1}{2}gt_2^2+v_0t_2+h_0

Combining equations 1,2,3 and setting h to zero:

0=-\frac{1}{2}gt_2^2+(at_1)t_2+\frac{1}{2}at_1^2\\ 0=a(t_1t_2+\frac{1}{2}t_1^2)-\frac{1}{2}gt_2^2

Solve for a with t₁ = 4s and t₂=2.1s:

a=\frac{1}{2}gt_2^2(\frac{1}{t_1t_2+\frac{1}{2}t_1^2})

7 0
3 years ago
3) A small, 30 gram pith ball carrying 3 nC of charge is dangling from an insulating string. Another charged pith ball carrying
ludmilkaskok [199]

Answer:

q2 = 5.1μC

Explanation:

From a forces diagram we can stablish that:

Fe = T*sin(16)              (eq1)

T*cos(16) = m*g           (eq2)

Where Fe is the electric force and T is the tension of the string. Solving for Fe:

Fe = m*g*tan(16)

The magnitude of the electric force is calculated as:

Fe = \frac{K*q1*q2}{d^2} = m*g*tan(16)  Solving for q2:

q2 = \frac{m*g*tan(16)*d^2}{K*q1}=5.1 \mu C

7 0
3 years ago
Read 2 more answers
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