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1 year ago

if the current through a resistor is increased by a factor of 4, how does this affect the power dissipated?

Physics

1 answer:

lbvjy [14]1 year ago

4 0

The new current will be 4I. The power dissipated by the resistor will increase by a factor of 16.

<h3>What is a resistor?</h3>

Using electrical resistance as a circuit element, a resistor is a passive electrical component with two terminals. In electrical circuits, resistors are used, among other things, to limit current flow, modify signal levels, divide voltages, bias active devices, and terminate transmission lines.

As test loads for generators, power distribution systems, and motor controls, high-power resistors that can create many watts of heat rather than just electrical energy can be used.

Variable resistors can be used as sensors for force, heat, light, humidity, humidity, and chemical activity or for adjusting circuit components.

Electrical networks and electronic circuits frequently contain resistors, which are found everywhere in electronic equipment. Practical resistors are discrete components that come in a wide range of materials and forms.

To learn more about resistor refer :

brainly.com/question/24858512

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The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 400 g. The vibra

Norma-Jean [14]

Answer:

1456 N

Explanation:

Given that

Frequency of the piano, f = 27.5 Hz

Entire length of the string, l = 2 m

Mass of the piano, m = 400 g

Length of the vibrating section of the string, L = 1.9 m

Tension needed, T = ?

The formula for the tension is represented as

T = 4mL²f²/ l, where

T = tension

m = mass

L = length of vibrating part

F = frequency

l = length of the whole part

If we substitute and apply the values we have Fri. The question, we would have

T = (4 * 0.4 * 1.9² * 27.5²) / 2

T = 4368.1 / 2

T = 1456 N

Thus, we could conclude that the tension needed to tune the string properly is 1456 N

4 0

3 years ago

Incident rays parallel to the principle axis of a concave mirror will reflect _____. parallel to the principle axis through the

Svetradugi [14.3K]

I’m not sure if its correct but I think it’s focal Ray point

For concave mirrors, some generalizations can be made to simplify ray construction. They are: An incident ray traveling parallel to the principal axis will reflect and pass through the focal point. An incident ray traveling through the focal point will reflect and travel parallel to the principal axis.

8 0

3 years ago

Read 2 more answers

The half-life of Co-55 is 175 hours. How much of a 4000 g of Cobalt-55 sample would be left after 525 hours?

Harrizon [31]

We know that whatever amount we start with, half of it decays and forms atoms of other elements in 175 hours. So in order to figure out how much is left after 525 hours, we'll need to know how many half-lifes pass in that amount of time.

Well, (525 divided by 175) is exactly 3 half-lifes. So this will be easy.

-- After 1 half-life . . .

. . . . . 50% decays, 50% is still there.

-- After the 2nd half-life . . .

. . . . . (half of the leftover 50%) = another 25% decays, 25% is left.

-- After the 3rd half-life . . .

. . . . . (half of the leftover 25%) = another 12.5% decays, 12.5% is left.

12.5% of 4,000g = (0.125 x 4,000g) = <em>500 g</em> .

============================================

<u>Another way</u>:

After 1 half-life, 1/2 is left.

After 2 half-lifes, 1/4 is left.

After 3 half-lifes, 1/8 is left.

1/8 of 4,000g = (4,000g/8) = <em>500 g </em>.

5 0

2 years ago

g The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)=−C6/x6, where C6 is a positi

Arisa [49]

Answer:

$F_x = -\frac{6 C_6}{2^7}$

Attractive

Explanation:

Data provided in the question

The potential energy of a pair of hydrogen atoms given by $\frac{C_6}{X_6}$

Based on the given information, the force that one atom exerts on the other is

Potential energy μ = $\frac{C_6}{X_6}$

Force exerted by one atom upon another

$F_x = \frac{\partial U}{\partial X} = \frac{\partial}{\partial X} (-\frac{C_6}{X^6})$

$F_x = \frac{\partial}{\partial X} (\frac{C_6}{X^6})$

$F_x = -\frac{6 C_6}{2^7}$

As we can see that the $C_6$ comes in positive and constant which represents that the force is negative that means the force is attractive in nature

5 0

3 years ago

What is the atomic mass of Jupiter?

lana [24]

The mass of Jupiter is 1.9 x 1027 kg.

4 0

3 years ago