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icang [17]
3 years ago
15

Two skaters begin at rest. Skater 1 has a smaller mass than Skater 2. After they push off each other,...

Physics
2 answers:
Vladimir [108]3 years ago
6 0

Answer:

C. Sakter 1 has Greater velocity than skater 2.

Explanation:

This concept can be explained using the concept of collision between two particles with different masses. When both the masses pull each other, smaller skater will acquire the greater velocity due to its less mass. While the greater skater will have lower velocity due to its greater mass. Hence, C is the right answer.

As the momentum is the product of mass and velocity, therefore change in momentum in both the skaters will be equal. It is obvious that both skaters have unequal masses and velocity but the product of mass and velocity for them is equal. Hence, option A and B are not right answers.

When both skaters pull each other, they exert force on each other. According to newton’s third law of motion action and reaction forces are equal and are in opposite direction. So, the forces which both skaters will experieces are equal. Hence, D is also not a right answer.

klasskru [66]3 years ago
3 0

As both the skater pushed each other with a force, skater 1 will acquire greater velocity than skater 2 with heavier mass.

Answer: Option C

<u>Explanation:</u>

Here we can understand the scenario with the example of a particle collision. When two particles of different masses, one being lighter and the other being heavier, there will be a movement and change in velocities.

Now, when these two particle collide with each other, there will be an equal and opposite thrust or reaction on both the particles. The particle with heavier mass will not be able to acquire more velocity because of its weight whereas the lighter particle will be pushed far away, being less in mass.

We can also say that the heavier particle will exert more force as compared to the lighter one and hence, can easily push it far away. this is all because the force is directly proportional to the mass of the object.

Hence, just like the particle, when two skater try to push each other with a significant amount of force, skater 2 will win to exert more force and therefore, skater 1 will acquire greater velocity as compared to skater 2.

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Geologists know the past temperature of the planet based on rock and fossil evidence. Why do you think it is difficult to determ
Basile [38]

Answer:

I think it is difficult to determine what has caused climate change in the distant past because it must have been a long time ago so geologists can't carry out different experiments and figure out what gases the planet had conjured, so geologists can only make predictions based off the evidence they currently have from what the planet looked like before. The planet must have changed over the years, therefore the climate has also changed in the future, so they cannot work with how the planet looked in the past.

7 0
3 years ago
Which statement best describes how light behaves with liquids, gases, and solids?
juin [17]

Answer:

C number is write i think

3 0
3 years ago
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
A figure skater glides along a circular path of radius 6.70 m. If she coasts around one half of the circle, find the following.
adoni [48]

(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

<h3>Distance of the skater from the starting position</h3>

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

Learn more about distance round a circle here: brainly.com/question/3100527

#SPJ1

8 0
2 years ago
A sprinter generates a constant force of 52 N as he runs 100 m. How much work did he do?
LUCKY_DIMON [66]
You just multiply these two numbers. It's 5200J, or 5.2kJ
3 0
4 years ago
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