Given refrelactive index n,
1/n = sinc
c = sin inverse (1/n)
Answer:
0.247 J = 247 mJ
Explanation:
From the principle of conservation of energy, the workdone by the applied force, W = kinetic energy change + electric potential energy change.
So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁) where m = mass of particle = 5.4 × 10⁻² kg, q = charge of particle = 5.10 × 10⁻⁵ C, v₁ = initial speed of particle = 2.00 m/s, v₂ = final speed of particle = 3.00 m/s, V₁ = potential at surface A = 5650 V, V₂ = potential at surface B = 7850 V.
So, W = ΔK + ΔU =1/2m(v₂² - v₁²) + q(V₂ - V₁)
= 1/2 × 5.4 × 10⁻²kg × ((3m/s)² - (2 m/s)²) + 5.10 × 10⁻⁵ C(7850 - 5650)
= 0.135 J + 0.11220 J
= 0.2472 J
≅ 0.247 J = 247 mJ
Answer:
Acceleration of the box is 4.9 m/s².
Explanation:
The free body diagram is shown below.
The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to 
acting along the incline.
Therefore, as per Newton's second law of motion,
Net force = 
Now, net force acting along the incline is only
Therefore,
Now, 
Therefore, the acceleration of the box is given as:
Acceleration of the box is 4.9 m/s².
<h3>Answers :</h3>
The gravitational field intensity (EG) or (g) is the force on a unit mass at a point in the field.
Since the force (F) on a body of mass m in a gravitational field of a body of mass M = GMm/r2 .
you can see that the force per unit mass is given by F/m. So:
Gravitational Field Intensity (EG) = (g) = F/m = GM/r2
The units for EG are N kg -1 or since F = ma, F/m = a and so EG may be expressed in ms -2
Hope this will help you :))
Do give this answer a brainliest :D
Longer I took a little physics but I remember them saying that a small star lasts longer than a larger star
