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3 years ago

One atomic model describes electrons moving in clouds around the nucleus.

Chemistry

1 answer:

bixtya [17]3 years ago

8 0

Answer: D. It is the currently accepted atomic model.

Explanation:

It is the mordern atomic model, also known as the Electron Cloud Model. Indicating that the nucleus of an atom is surrounded by a cloud of electrons.

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What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???

melamori03 [73]

Answer:

The answer to your question is: 16.7 g of KBr

Explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

= 0.14

MW KBr = 39 + 80 = 119 g

119 g of KBr -------------------- 1 mol

x -------------------- 0.14 mol

x = (0.14 x 119) / 1

x = 16.7 g of KBr

8 0

3 years ago

Read 2 more answers

How many moles of hydrogen are there, if there are 4 molecules of hydrogen?

Scorpion4ik [409]

Answer:

Explanation:

In this case, according to the Periodic table

there is 1g of hydrogen per mole. As we know that dihydrogen (H2) has two hydrogen atoms per molecule. So,there will be 2*1g hydrogen per mole=2g dihydrogen per mole.

If there is 2g dihydrogen per mole,and we have 4g,then we know that there is 2 mole dihydrogen in 4g.And for hydrogen there is 4 moles in 4g of hydrogen

5 0

3 years ago

Please answer C...........

sergij07 [2.7K]

CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

2,3-dimethyl-1-butane

Explanation:

We have the following chemical reaction:

CH₂=C(-CH₃)-CH(-CH₃)-CH₃ + H₂ → CH₃-CH(-CH₃)-CH(-CH₃)-CH₃

So 2,3-dimethyl-1-butene will react with hydrogen to produce 2,3-dimethyl-1-butane.

Learn more about:

hydrogenation of double bonds in organic compounds

brainly.com/question/5793623

brainly.com/question/4591261

#learnwithBrainly

4 0

4 years ago

The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N

masha68 [24]

Answer: The amount of nitrogen gas produced is 3.864 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $NaN_3$ = 6.00 g

Molar mass of $NaN_3$ = 65 g/mol

Putting values in equation 1, we get:

$\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol$

For the given chemical reaction:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

So, 0.092 moles of $NaN_3$ will produce = $\frac{3}{2}\times 0.092=0.138mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

$0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g$

Hence, the amount of nitrogen gas produced is 3.864 grams

7 0

3 years ago

Nitrogen and hydrogen gases react to form ammonia gas via the following reaction:

Luda [366]

1mol N2 + 3mol H2 → 2mol NH3
Because you are dealing with gases, at the same temperature and pressure you can say: 
1volume N2 + 3 volumes H2 → 2 volumes NH3 
OR: 4 volumes reactants = 2 volumes products. 
You have 1.9+5.7 = 7.6 volumes reactants, which must give 7.6/2 = 3.8 volumes of NH3 
Answer: 3.8 litres of NH3 will be formed

7 0

3 years ago