Answer:
a. 0.119mol Kr
Explanation:
To solve this problem, we must understand that;
Mass = number of moles x molar mass
Molar mass of Kr = 83.3g/mol
Ar = 40g/mol
He = 4g/mol
Ne = 20.18g/mol
a0.119 mol Kr mass = 0.119 x 83.3 = 9.9g
b 0.400 mol Ar mass = 0.4 x 40 = 16g
C 1.25 mol He mass = 1.25 x 4 = 5g
d 2.02 mol Ne mass = 2.02 x 20.18 = 40.8
Krypton is the answer
Number 2 lower entropy and higher entropy
I think the answer is einsteinium is the heavier one here.
Answer:
5-chloro-2-methylcyclohexanol
Explanation:
There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.
IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. <em><u>In this case, the priority functional group is the alcohol group</u></em>, <u><em>so we will start the counting of the carbons in this group.</em></u> Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, <em><u>in this case, we can assign the number 2 to the methyl group and 5 to the chloride group</u></em>, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.
Since the other options involve: <u>high countings for the susbtituents groups (</u><u>3</u><u>-chloro-</u><u>6</u><u>-methylcyclohexanol)</u>, <u>wrong assignation of priority functional group (</u><u>1-chloro</u><u>-4-methylcyclohexanol), wrong sequence of counting in the compound (</u><u>2-methyl-3-chloro</u><u>cyclohexanol) and no alphabetical order to name the compound (2-</u><u>methyl</u><u>-5-</u><u>chloro</u><u>cyclohexanol), </u><u>the correct option is:</u>
5-chloro-2-methylcyclohexanol
Have a nice day!
First, in order to calculate the specific heat capacity of the metal in help in identifying it, we must find the heat absorbed by the calorimeter using:
Energy = mass * specific heat capacity * change in temperature
Q = 250 * 1.035 * (11.08 - 10)
Q = 279.45 cal/g
Next, we use the same formula for the metal as the heat absorbed by the calorimeter is equal to the heal released by the metal.
-279.45 = 50 * c * (11.08 - 45) [minus sign added as energy released]
c = 0.165
The specific heat capacity of the metal is 0.165 cal/gC
