Answer:
About 0.08486 moles
Explanation:
PV=nRT, when P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

moles
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Explanation:
The given data is as follows.
50 ml of
, 50 ml of 
And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.
(As 1 L = 1000 ml)
=
moles
So, according to the given equation
moles of
reacts with
moles of
.
Hence, moles of
is equal to the moles of
and
.
Therefore, moles of
=
moles
1 mole of
= 22.4 L
moles =
= 50 ml of product
Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.
Answer:
0.045 moles
Explanation:
Given data:
Moles of CO = ?
Volume of gas = 1 L
Temperature and pressure = standard
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm× 1L / 0.0821 atm.L/mol.K × 273 K
n = 1 atm.L / 22.41 atm.L/mol
n = 0.045 mol
Henri Becquerel discovered radioactivity and it was the Curies who made experiments about the concept and became known for their d
Answer:(3)
Explanation: 2Al+3H2SO4----->Al(2SO4)3+3H2