Answer:
1.3 L
Explanation:
The volume of a rectangular cube can be calculated using the following formula:
Volume (L) = length (cm) x width (cm) x height (cm)
Keep in mind that 1 L = 1,000 cm³.
Before you can plug the values into the equation, you need to make sure they all have the same unit. Since the length is in meters (m), you need to first convert it to centimeters.
1 meter = 100 cm
0.159 m 100 cm
--------------- x ---------------- = 15.9 cm
1 m
Now, you can solve for the volume. To find the answer is the unit liters, you need to divide the volume by 1,000.
Volume = l x w x h
Volume = 15.9 cm x 10.5 cm x 7.7 cm
Volume = 1,285.5 cm³
Volume = 1.2855 L ------> Volume = 1.3 L
Answer:
Molarity is the number of moles in a liter of a substance.
Molarity= Mole/volume
Mass= 10g
Molar mass of Carbon=12g
To calculate the mole we use the formula: mole= mass/molar mass
Mole = 10g/12g
Mole = 0.83
Molarity= 0.83/500 =0.0017moles per liter
<span>Answer:
H-C-N H-N-C C-H-N
Notice that C-H-N is the same as N-H-C just written backwards. ( i.e. they have the same connectivtiy.) You can exclude the last one with H in the middle since H has two bonds and 4 electrons around it. At this point you couldn't differentiate between the first two, so I would give you the connectivity in such a problem, which in this case is H-C-N.</span>
Answer: 2.8 moles
Explanation:
The balanced equation below shows that 1 mole of sodium oxide reacts with 1 mole of water to form 2 moles of sodium hydroxide respectively.
Na2O + H2O --> 2NaOH
1 mole of H2O = 2 moles of NaOH
Let Z moles of H2O = 5.6 mole of NaOH
To get the value of Z, cross multiply
5.6 moles x 1 mole= Z x 2 moles
5.6 = 2Z
Divide both sides by 2
5.6/2 = 2Z/2
2.8 = Z
Thus, 2.8moles of H2O are needed to produce 5.6 mol of NaOH
1- thé everyday use of kinematic basically the speed for something it’s the magnitude.
2-the speed of something in a certain direction
2a- They are both related by speed.
3-the capacity of a vehicle which gains speed in a short time
4-it’s an attraction of all matter (not sure on this one)
