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klemol [59]
3 years ago
7

The current in a hair dryer measures 11 amps. The resistance of the hair dryer is 15 ohms. What is the voltage? Your Answer: Que

stion 12 options: Answer: units:
Physics
1 answer:
lorasvet [3.4K]3 years ago
5 0
V=IR
V=15x11
V=165ohms

I don’t quite remember the unit

Ohms law
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Natalie lifts a 15-kg rock from the ground onto a 1.5 meter high wall. what is the amount of potential energy she has given the
Zina [86]
The amount of gravitational potential energy acquired by the rock is equal to:
\Delta U = mg \Delta h
where 
m is the mass of the rock
g is the gravitational acceleration
\Delta h is the increase in height of the rock

Substituting the data of the problem, we find
\Delta U=(15 kg)(9.81 m/s^2)(1.5 m)=220.7 J
So, Natalie gave 220.7 J of energy to the rock.
4 0
3 years ago
A nonconducting container filled with 25 kg of water at 23°C is fitted with a stirrer, which is made to turn by gravity acting o
Paul [167]

Explanation:

Given that,

Weight of water = 25 kg

Temperature = 23°C

Weight of mass = 32 kg

Distance = 5 m

(a). We need to calculate the amount of work done on the water

Using formula of work done

W=mgh

W=32\times9.8\times5

W=1568\ J

The amount of work done on the water is 1568 J.

(b). We need to calculate the internal-energy change of the water

Using formula of internal energy

The change in internal energy of the water equal to the amount of the  work done on the water.

\Delta U=W

\Delta U=1568\ J

The  change in internal energy is 1568 J.

(c). We need to calculate the final temperature of the water

Using formula of the change internal energy

\Delta U=mc_{p}\Delta T

\Delta U=mc_{p}(T_{2}-T_{1})

T_{2}=T_{1}+\dfrac{\Delta U}{mc_{p}}

T_{2}=23+\dfrac{1568}{25\times4.18\times10^{3}}

T_{2}=23.01^{\circ}\ C

The final temperature of the water is 23.01°C.

(d). The amount of heat removed from the water to return it to it initial temperature is the change in internal energy.

The amount of heat is 1568 J.

Hence, This is the required solution.

6 0
3 years ago
A pendulum has a mass of 3kg and is lifted to a height of .3m. What is the maximum speed of the pendulum
Kryger [21]

Given data

*The given mass of the pendulum is m = 3 kg

*The given height is h = 0.3 m

The formula for the maximum speed of the pendulum is given as

v_{\max }=\sqrt[]{2gh}

*Here g is the acceleration due to the gravity

Substitute the values in the above expression as

\begin{gathered} v_{\max }=\sqrt[]{2\times9.8\times0.3} \\ =2.42\text{ m/s} \end{gathered}

Hence, the maximum speed of the pendulum is 2.42 m/s

7 0
1 year ago
Which three terms are needed to describe the energy a BASE jumper has as she falls toward the ground?
Thepotemich [5.8K]

Answer:

Potential energy

Kinetic energy

Gravitational energy.

Explanation:

The potential energy is the stored energy, it is the energy and object posses at rest. When the base jumper is still at rest i.e without motion, she has potential energy.

Gravitational energy this refer to the potential energy an object or body with mass posses in relation to another object due to gravity.

This is seen when the base number is still at rest and the force of gravity on the Earth acting on her.

Kinetic energy is the energy posses by an object or body in motion.

As the base jumper falls to the ground, she posses kinetic energy which is the energy in motion.

4 0
3 years ago
Two forces F1 and F2 are acting on a block of mass m=1.5 kg. The magnitude of
nika2105 [10]

Answer:

Explanation:

Component of force F₁ in right direction = F₁cos37

= 12 x cos37 = 9.58 N .

Component of force F₂ in  vertically upward direction = F₁sin37

= 12 x sin37 = 7.22 N .

a ) Let normal force be R

R + F₁sin37  = mg

R + 7.22 = 1.5 x 9.8 = 14.7

R = 7.48 N .

b )

Net force in horizontal direction = F₂ - F₁cos37

= F₂ - 9.58

This is equal to zero as body is moving with zero acceleration

F₂ - 9.58 = 0

F₂ = 9.58 N

c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂

F₂ - 9.58 = 1.5 x 2.5 = 3.75

F₂ = 13.33 N .

6 0
3 years ago
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