This is because they need lots if water to grow
PV = nRT
A gas at STP... This means that the temperature is 0°C and pressure is 1 atm.
R is the gas constant which is 0.08206 L*atm/(K*mol)
Rearranging for volume
V = nRT/P
The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)
PV = k
where k is a constant.
This means that
P₁V₁ = k = P₂V₂
P₁V₁ = P₂V₂
(1 atm) * (1 L) = (2 atm) * V₂
V₂ = 0.5 L
The new volume of the gas is 0.5 L.
In the afternoons the prevailing<span> direction is South-East with recurrent low </span>wind<span> and calm that averages 30%. Overcast (cloudy): Lima has a lot of months under ...</span>
Explanation:
a.H2PO4 + 2KOH = K2PO4 + 2H2O
b. H2PO4 _ 2KOH
1(2) + 31 + 16(4) _ 2(23) + 2(16) + 2(1)
2 + 31 + 64 _ 46 + 32 + 2
97 _ 80
no of moles of H2PO4 = 2.5 ÷ 97
= 0.026mol
no of moles of 2KOH = 4 ÷ 80
= 0.05mol
2KOH is the limiting reactant
c. H2PO4 is the excess reactant
d. 1 mole H2PO4 weighs 2.5g
0.026mol H2PO4 weighs g
(0.026 × 2.5)
H2PO4 weighed 0.065g after reaction
Answer:
480 L
Explanation:
In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.
As we can see, Charles's Law is:

or, initial volume over initial temperature equals final volume over final temperature.
In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for
:
--------------------------------------------------------------------------------------------------------------
(60) / (0.5) =
/ (4)
↓
120 =
/ 4
×4 ×4
↓
= 480 L
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There's our answer! Feel free to comment if you have any questions about my answer :)