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podryga [215]
3 years ago
13

Which of the following is an essential condition for a redox reaction?

Chemistry
2 answers:
rusak2 [61]3 years ago
8 0
The oxidation of at least two atoms should change
Contact [7]3 years ago
5 0

<u>Answer:</u> The correct answer is the oxidation state of at least two atoms should change.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction reaction takes place simultaneously.

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

In a redox reaction, oxidation state of at least two atoms should change because here exchange of electrons takes place.

<u>For Example:</u> The reaction of copper with silver nitrate, the equation follows:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The half reactions for the above reaction are:

Oxidation half reaction:  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

Reduction half reaction:  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

Oxidation state of copper and silver is getting changed to its respective ions.

Hence, the correct answer is the oxidation state of at least two atoms should change.

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The substance ammonia has the following properties: normal melting point: 195.4 K normal boiling point: 239.8 K triple point: 5.
Olenka [21]

Answer:

a) Superficial fluid

b)  5.9*10^-2 atm

c) Gas

d) Liquid

e) Solid

Explanation:

a)  At temperatures above 405.5 K and pressures above 111.5 atm, NH3 is a superficial fluid because liquid and gases does not exit at temperature and pressure greater than  405.5 K and  111.5 atm

b) NH3 does not exist as a liquid at pressures below  5.9*10^-2 atm , That is below the triple point there is existence of liquid

c)  NH3 is a Gas at 5.90×10^-2 atm and 249.5 K.

d) NH3 is a  Liquid  at 1.00 atm and 236.0 K. because pressure and temperature ( standard ) is between the given normal melting and boiling point

e) NH3 is a solid at 24.6 atm and 185.6 K . because the pressure here is more than that of triple point while the temperature is lesser

7 0
3 years ago
90.0 mL of H2O is initially at room temperature (22.0∘C). A chilled steel rod at 2.0∘C is placed in the water. If the final temp
Flura [38]

Answer:

The steel bar weighs 39.014 grams

Explanation:

Heat lost by water = - heat gained by steel

m(water) = 90 grams

m(steel) = TO BE DETERMINED

specific heat of water = 4.18 J/g°C

specific heat of steel = 0.452 J/g°C

Initial temperature T1 water = 22°C

Final temperature T2 water = 21.1 °C

Initial temperature T1 steel = 2°C

Final temperature T2 steel = 21.1°C

Heat transfer = m*Cp*ΔT

with Cp = specific heat

with ΔT = Change of temperature = T2 - T1

m(water) * Cp(water) * ΔT(water) = m(steel) *Cp(steel) *ΔT(steel)

90g * 4.18 * ( 21.1 - 22) = -m(steel) * 0.452 * (21.1-2)

-338.58  = - m(steel)*8.6784

m(steel) = 39.014 grams

The steel bar weighs 39.014 grams

8 0
3 years ago
Which of the following bonds is the strongest?
mr Goodwill [35]
The answer to this question will be c
3 0
3 years ago
When the equation Fe + O2→Fe2O3 is balanced, the coefficient for O2 is:
ollegr [7]
The fully balanced equation would be 

4Fe + 3O2 --> 2Fe2O3

for each side, we have

4 Fe (4 iron)
6 Oxygen (O)

So the final answer is choice B) 3
7 0
3 years ago
Read 2 more answers
Dissolving 4.02 g of CaCl2 in enough water to make 349 mL of solution causes the temperature of the solution to increase by 3.91
gregori [183]

Answer:

ΔH per mole of CaCl2 is 160.3 kJ

Explanation:

<u>Step 1: </u>The balanced equation

CaCl2 (aq)→  Ca2+  +  2Cl-(aq)

<u>Step 2:</u> Data given

Molar mass of CaCl2 =110.98 g/mole

mass of CaCl2 = 4.02 grams

volume of the solution = 349 mL = 0.349 L

Temperature increases with 3.91 °C

Specific heat of the solution = specific hea of water = 4.18 J/°C*g

Density solution = density water = 1g/cm³

<u>Step 3:</u> Calculate moles of CaCl2

Numer of moles of CaCl2 = mass of CaCl2 / Molar mass of CaCl2

Number of moles = 4.02 grams /110.98 g/mole= 0.036 moles

<u>Step 4</u> = Calculate amount of heat added

Q = m*c*ΔT

with m = the mass 349 grams + 4.02 grams = 353.02 grams

c = 4.18 J/°C*g

ΔT = 3.91 °C

Q = 353.02*4.18*3.91 = 5769.69 J

Step 5: Calculate ΔH per mole

5769.69 J /0.036 moles = 160269.1 J = 160.3 kJ

ΔH per mole of CaCl2 is 160.3 kJ

6 0
3 years ago
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