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2 years ago

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

Chemistry

1 answer:

Artemon [7]2 years ago

8 0

<h3>Answer:</h3>

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

<h3>Explanation:</h3>

Balanced equations are equations that obey the law of conservation of mass.
When an equation is balanced the number of atoms of each element is equal on both side of the equation.

Equations are balanced by putting appropriate coefficients on the reactants and products.
In our case, we are going to put coefficients 2, 1 and 1.

Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.

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The equilibrium concentrations of the reactants and products are [HA]=0.280 M, [H+]=4.00×10−4 M, and [A−]=4.00×10−4 M. Calculate

Tems11 [23]

Answer:

6.24

Explanation:

The following data were obtained from the question:

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

pKa =.?

Next, we shall write the balanced equation for the reaction. This is given below:

HA <===> H+ + A-

Next, we shall determine the equilibrium constant Ka for the reaction. This can be obtained as follow:

Equilibrium constant for a reaction is simply the ratio of concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

The equilibrium constant for the above equation is given below:

Ka = [H+] [A−] /[HA]

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

Equilibrium constant (Ka) =

Ka = (4×10¯⁴ × 4×10¯⁴) / 0.280

Ka = 1.6×10¯⁷/ 0.280

Ka = 5.71×10¯⁷

Therefore, the equilibrium constant for the reaction is 5.71×10¯⁷

Finally, we shall determine the pka for the reaction as follow:

Equilibrium constant, Ka = 5.71×10¯⁷

pKa =?

pKa = – Log Ka

pKa = – Log 5.71×10¯⁷

pKa = 6.24

Therefore, the pka for the reaction is 6.24.

6 0

2 years ago

Bob adds heat to a substance. When enough heat is added, A. its particles move closer together and the substance becomes a gas.

Elena L [17]

Answer:

C. its particles move farther apart and the substance becomes a gas.

Explanation:

A. is wrong because moving closer together creates a solid, not a gas.

B. is wrong because moving father apart creates a gas, not solid.

C. is correct because moving farther apart creates a gas.

D. is wrong because when heat is added particles spread apart because they vibrate faster. Although, in a solid the particles are closer together.

- Just know the states of matter and how the particles move and that will help with this problem.

6 0

2 years ago

A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio

-Dominant- [34]

<em>Answer:</em>

The concentration of new solution will be 1×10∧-7 M.

<em>Solution:</em>

<em>Data Given </em>

given mass of fluoxymesterone =16.8mg = 0.0168 g

molar mass of fluoxymesterone = 336g/mol

vol. of fluoxymesterone = 500.0 ml = 0.500 L

Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

Stock Solution : New Solution

M1.V1 = M2.V2

( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

1 × 10∧-7 = M2

<em>Result:</em>

The concentration of new solution M2 will be 1 × 10∧-7

3 0

3 years ago

The half-life of sr-90 is 28 years. after 56 years of decay only 0. 40 g of a sample remains. what was the mass of the original

Svetradugi [14.3K]

Half-life is the time taken for the concentration of the substance to reduce by 50%. The original sample of strontium had a mass of 1.6 gms. Thus, option d is correct.

The half-life of any radioactive substance is the time period at which the concentration will get reduced to half the initial amount. The initial mass of Sr-90 is calculated as,

$N(t) = N_{0} (\dfrac{1}{2})^{ \frac{t }{t 1/2}}$

Given,

Quantity of the remaining substance N (t) = 0.40 gm

Initial radioactive substance quantity $N_{0}$ =?

Time duration (t) = 56 years

Half-life = 28 years

Substituting values above:

$\begin{aligned} 0.40 &= N_{0} (\dfrac{1}{2}) ^{{\frac{56}{28}}\\\\0.40 &= N_{0} (\dfrac{1}{2})^{2}\end{aligned}$

= 1.6 gm

Therefore, option d. the initial mass of Sr is 1.6 gm.

Learn more about half-life here:

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7 0

1 year ago

After the recycled plastic is released from the machine into the brick mold, explain what will happen to the kinetic energy in t

Rina8888 [55]

Answer: Depending on the data and the patterns, sometimes we can see that pattern in a simple tabular presentation of the data. Other times, it helps to visualize the data in a chart, like a time series, line graph, or scatter plot.

Explanation:

1960 5.91

1970 5.59

1980 4.83

1990 4.05

2000 3.31

2010 2.60

8 0

2 years ago