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Dmitriy789 [7]
3 years ago
10

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

Chemistry
1 answer:
Artemon [7]3 years ago
8 0
<h3>Answer:</h3>

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

<h3>Explanation:</h3>
  • Balanced equations are equations that obey the law of conservation of mass.
  • When an equation is balanced the number of atoms of each element is equal on both side of the equation.
  • Equations are balanced by putting appropriate coefficients on the reactants and products.
  • In our case, we are going to put coefficients 2, 1 and 1.
  • Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

  • This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
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Atomic mass i believe..

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The first table was arranged by atomic mass, but later Mosely improved it by arranging by _______________.
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Order of increasing atomic mass!

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6 0
3 years ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
An atom of gold has a mass of 3.271 x 10-22g. How many atoms of gold are in 5.00g of gold?
rosijanka [135]
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation  \frac{mass of gold}{mass of gold atom}. 

Let x be the number of gold atoms. Plug in the values to a calculator.

x = \frac{5.00g}{3.271 x 10-22g}
Both have the same units so the unit gram(g) can be cancelled. 
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
3 0
4 years ago
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