Answer:
The location of the shear center o is 0.033 or 33 m
Explanation:
Solution
Recall that,
The moment of inertia of the section is = I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12
= 30 * 10 ^ ⁻⁶ m⁴
Now,
The first moment of inertia is
Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)
= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²
Thus,
The shear flow is,
q = VQ/I
so,
P = (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶
P = (16.67 x - 83. 33 x²)
The shear force resisted by the shorter web becomes
Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33 x²) dx = 0.11x
Then,
We take the moment at a point A
∑Mₐ = 0
- ( p * e)- (Vw₂ * 0.3 ) = 0
e = 0.11 p * 0.3/p
which gives us 0.033 m
= 33 m
Therefore the location of the shear center o is 0.033 or 33 m
Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.
Answer:
<u>Atom</u><u> </u><u>is </u><u>particle</u><u> </u><u>of </u><u>matter</u><u> </u><u>that </u><u>uniquely</u><u> </u><u>defines</u><u> </u><u>a</u><u> </u><u>chemical</u><u> </u><u>element</u><u>.</u>
Examples of atom:
- Hydrogen [ H]
- Neon [Ne]
- Argon [A]
- Iron [Fe]
- Calcium [Ca]
<h3>
About Atom:</h3>
Atom consists of a central nucleus that is usually surrounded by one or more electrons .Each electron is negatively charged. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.
An early model of the atom was developed by the physicist Ernest Rutherford in 1913. He was the first to suggest that atoms are like miniature solar systems except that the attractive force is not caused by gravity, but by opposing electrical charged.
Hope this helps....
Good luck on your assignment...
It’s c and a I believe ask someone else to make sure but I’m pretty sure
