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ollegr [7]
3 years ago
15

The atom in the diagram has a neutral charge how many protons does it have

Physics
1 answer:
Olegator [25]3 years ago
8 0

Explanation:

This should be of help:

An atom is made up of three subatomic particles:

  • Protons are the positively charged particles.
  • Electrons are the negatively charged particles.
  • Neutrons do not carry any charges.

A neutral atom is an atom that has not lost or gained any amount of electrons.

In a neutral atom;

                the number of protons and electrons are the same

 Usually atoms are designated this way:

                                                  ᵃₙX

  where X is the symbol of the atom

               a is the mass number of the atom

                n is the atomic number of the atom

 The mass number = number of protons + number of neutrons

        Atomic number = number of protons

Note; atomic number is the same as the number protons and the number of electrons in a neutral atom.

Use this guide to solve the problem

Learn more:

Atomic number brainly.com/question/5425825

#learnwithBrainly

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A 7382 N piano is to be pushed up a(n) 2.16 m frictionless plank that makes an angle of 22.7 ◦ with the horizontal. Calculate th
lubasha [3.4K]

Answer:

Work done, W = 6153.31 Joules

Explanation:

It is given that,

Weight of piano, W = F = 7382 N

It is pushed 2.16 meters friction less plank

The angle with horizontal, \theta=22.7^{\circ}

When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :

F_y=F\ sin\theta

Work done is given by :

W=F_y\times d

W=F\ sin\theta \times d

W=7382 sin(22.7) \times 2.16

W = 6153.31 Joules

So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.

7 0
3 years ago
a physical science textbook has a mass of 2.2 kg. If the textbook weighs 19.6 newtons on Venus, what is the strength of gravity
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8 0
3 years ago
Read 2 more answers
An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res
murzikaleks [220]

Answer:

(a) V=11.86\ V

(b) V=9.76\ V

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

V=R.I

(a) The electromagnetic force of the battery is \varepsilon =12.6\ V and its internal resistance is R_i=0.06\ \Omega. Knowing the equivalent resistance of the headlights is R_e=5.2\ \Omega, we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)

Solving for i

\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A

i=2.28\ A

The potential difference across the headlight  bulbs is

V=\varepsilon  -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V

V=11.86\ V

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

V=\varepsilon  -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V

5 0
3 years ago
Jayden was given a marshmallow and a syringe in class to experiment with. She placed the marshmallow in the syringe and sealed t
Tju [1.3M]
<h2>Answer:</h2>

The correct option is A.

A) The increased pressure, pushed the molecules closer together, and caused the marshmallow to shrink.

<h2>Explanation:</h2>

Jayden experimented, she placed the marshmallow in the syringe and sealed the end. When she depressed the plunger of the syringe, the pressure increased and pushed the molecules closer together and causes the marshmallow to shrink.

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3 0
3 years ago
One mol of a perfect, monatomic gas expands reversibly and isothermally at 300 K from a pressure of 10 atm to a pressure of 2 at
Zolol [24]

Answer:

Explanation:

Given

1 mole of perfect, monoatomic gas

initial Temperature(T_i)=300 K

P_i=10 atm

P_f=2 atm

Work done in iso-thermal process=P_iV_iln\frac{P_i}{P_f}

P_i=initial pressure

P_f=Final Pressure

W=10\times 2.463\times ln\frac{10}{2}=39.64 J

Since it is a iso-thermal process therefore q=w

Therefore q=39.64 J

(b)if the gas expands by the same amount again isotherm-ally and irreversibly

work done is=P\Delta V

V_1=\frac{RT_1}{P_1}=\frac{1\times 0.0821\times 300}{10}=2.463 L

V_2=\frac{RT_2}{P_2}=\frac{1\times 0.0821\times 300}{2}=12.315 L

\Delta W=1\times (12.315-2.463)=9.852 J

\Delta q=\Delta W=9.852 J

\Delta U=0

8 0
3 years ago
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