Answer: Rubber source, temperature, thinkness, thread design, driving pattenrs, weather, etc.
Explanation: There are many variables. Here are a few I would include in a tire lifetime study:
1. Type of rubber, including source
2. Thickness of tire
3. Design of tire thread
4. Life as a function of average speed and road surface
5. Expected outside temperature and wet conditions
6. Driving conditions of speed and both acceleration and deceleration parameters (e.g., tire life when slamming on the brakes or accelerating quickly)
The osmotic pressure of a solution is a colligative property, which means that it depends on the number of particles of solute in the solution.
Formula: Osmotic pressure = MRT, where M is the molarity of the solution, R is the universal constant of ideal gases and T is the absolute temperature of the solution.
So, the answer is the option .: the osmotic pressure of a solution increases as the number of particles of solute in the solution increases.
Answer: 5
Explanation: nitrogen has atomic number of 7 and its electronic configuration is 2, 5.
5 is the number of electrons in the outermost shell
Answer:
i) 0,7 molH20/s
ii)11,2 g O/s
iii)1,4 g H/s
Explanation:
i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):
