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3 years ago

A car moves at 18m/s North. What is the x component of the velocity?

Physics

1 answer:

Marina86 [1]3 years ago

6 0

Velocity, v = 18 m/s, makes an angle 60 degrees with the horizontal (x-axis).

(horizontal) x-component of velocity, v(x) = v cos (60) = 18 m/s x cos(60) = 9 m/s

If you need to determine the y-component (vertical) of velocity,

(vertical) y-component of velocity, v(y) = v sin (60) = 18 m/s x sin(60) = 15.6 m/s

Hope it helps

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Explanation:

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We divide the first equation by the second equation to get:

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$A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8} \ m^2$

Using this Area, we find the diameter of the wire:

$D = \sqrt{\frac{4A}{\pi}}$

$D = \sqrt{\frac{4 \times 3.8 \times 10^{-8} }{\pi}}$

$D = 0.00011 \ m = 1.1 \times 10^ {-4} = 0.11 \ mm$

To find the length, we multiply the two equations stated initially:

$mR = d\rho l^2\\\\l^2 = \frac{mR}{d\rho} \\\l^2 = \frac {1.0 \times 10^{-3} \times 1.3}{8960 \times 1.7\times 10^{-8}}$

$l^2 = 8.534\\l = 2.92 \ m$

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hope this helps