Answer:
The induced current is 0.084 A
Explanation:
the area given by the exercise is
A = 200 cm^2 = 200x10^-4 m^2
R = 5 Ω
N = 7 turns
The formula of the emf induced according to Faraday's law is equal to:
ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt
Replacing values:
ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V
the induced current is equal to:
I = ε /R = 0.42/5 = 0.084 A
Conducting because it occurs when two objects touch and heat is transferred
You can do 50 and 10 and carry the 30 and it would be in the same power so you’ll have the same energy
<u>In modern physics</u>, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T
as:
where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.
then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:
As
Then
then
- The factor will the total energy radiated per second per square meter increase = 256
Answer:
16 kg
Explanation:
M - container
m - oil mass
by definition of density ,
relative density is the ratio of the density of a substance to the density of water.
relative density = density/ density of water
density of oil = 1.2*1000 kgm⁻³ = 1200 kgm⁻³
1 Litre =10⁻³ m³
oil volume = 80 *10⁻³ m³
mass of oil = density * volume
= 1200*80*10⁻³
= 96 kg
Mass of container + mass of oil =112
mass of container = 112 - 96
= 16 kg
