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Anastasy [175]
2 years ago
11

A training pyramid increases general physical preparedness, facilitating foundational strength and reducing the risk of injury.

the purpose of the model is to build a strong foundation over time, eliminating any structural deficit the lifter may possess.
a) true
b) false
Physics
1 answer:
liubo4ka [24]2 years ago
7 0

The statement given about a training pyramid is a) True

<h3>Meaning of  a Training pyramid</h3>

A training pyramid can be defined with a pyramid in view where there are different steps from bottom to top.

A training pyramid is a training process that starts with easy and simple training tasks to difficult and hard task.

In a pyramid system you get to build step by step.

In conclusion, The statement given about a training pyramid is a) True

Learn more about a Training pyramid: https://brainly.in/question/9515867

#SPJ1

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Question 8 of 10
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B. Venus hope this helps have a great day
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3 years ago
A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate
PilotLPTM [1.2K]

Answer:

T(1)=21

Explanation:

The equation of the position in kinematics is given:

x(t)=x_{0}+v_{0}t+0.5at^{2}

  • x(0) is the initial position, in this it is 0
  • v(0) is the initial velocity (20 m/s)
  • a is the acceleration (2 m/s²)

So the equation will be:

x(t)=20t+0.5*2*t^{2}

x(t)=20t+t^{2}    

Now, the Taylor polynomial equation is:

f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.

f(t)=x(t)=20t+t^{2}

f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t

f''(t)=\frac{dv(t)}{dt}=a(t)=2

Using the Taylor polynomial with a = 0 and take just the second order of the derivative.

f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}

f(0)=x(0)=0

f'(0)=v(0)=20

f''(0)=a(0)=2

T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}

T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}

T(t)=20t+t^{2}

Let's put t=1 so find the how far the car moves in the next second:

T(1)=20*1+1^{2}

T(1)=21

Therefore, the position in the next second is 21 m.

We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.

I hope it helps you!

4 0
3 years ago
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