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V125BC [204]
2 years ago
11

How many mol of lithium are there in 1.204 x 1024 lithium atoms

Chemistry
1 answer:
konstantin123 [22]2 years ago
8 0

Answer:

The answer is

<h2>2.0 moles</h2>

Explanation:

To find the number of moles of an element given the number of entities contained in that element , we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.204 × 10²⁴ lithium atoms

We have

n =  \frac{1.204 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>2 moles</h3>

Hope this helps you

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Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise
USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

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change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

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Pressure in reactant side;

0.110 - 2x

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The integral rate law expression is given as;

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ln (0.0834/0.11) = (7.48*10^-3)  t

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3 0
2 years ago
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Explanation:

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Answer:

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3 years ago
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