Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
<em>Where:</em>
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
<h3>49.5J/°C</h3>
<em />
The only list containing molecules is list #4
NaCl, N2, and H2O are all made up of more than one element, making them molecules. The other lists contain an element. Mg, He, and Fe are elements, not molecules.
Hope this helps!
Answer : The mass of sucrose added to water will be, 189.0 grams.
Explanation :
As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.
Total given volume of solution = 2.1 L = 2100 mL (1 L = 1000 mL)
Now we have to determine the mass of sucrose in solution.
As, 100 mL of solution contains 9 grams of sucrose
So, 2100 mL of solution contains 
grams of sucrose
Therefore, the mass of sucrose added to water will be, 189.0 grams.
<u>Answer:</u>
70 kilometers per hour
<u>Explanation:</u>
280 kilometers ÷ 4 hours (7:00 pm - 3:00 pm = 4 hours) = 70 kilometers per hour
<em>Hope this helps! Sorry if wrong. You are loved and you are beautiful/handsome!</em>
-Bee
