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zubka84 [21]
4 years ago
9

In which of these would a nonpolar covalent bond be present? HBr H2O HCI Br2

Chemistry
1 answer:
cluponka [151]4 years ago
5 0
Br2 is the correct answer
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If the change in Gibbs free energy for a process is positive, the corresponding change in entropy for the universe will be
Gnesinka [82]

If the change in Gibbs free energy for a process is positive, the corresponding change in entropy for the universe will be positive.

<h3>What is Gibbs free energy?</h3>

This is defined as the energy used by a substance involved in a chemical reaction.

The Gibbs free energy and entropy has a direct relationship which is why a positive gibbs free energy will result in a corresponding positive entropy.

Read more about Gibbs free energy here brainly.com/question/9179942

4 0
3 years ago
In the same science fair,Tina ask the question "does caffeine increase the heart rate of an earthworm?" In test 1,she measures t
Alborosie
<span>The independent variable is the one that does not change depending on other variables - so here it would be the presence or the absence of caffeine - this is dependent on Tina's actions, but not on other variables in the experiment. The dependent variable is the heart rate - it is assumed to depend on the presence or absence of caffeine. A hypothesis could be that "Caffeine causes an increase of heart rate in earthworms" - and this hypothesis is what the experiment is testing.</span>
5 0
3 years ago
Determina el pH de una solución si la concentración de H es 3.5 x 10 molar, e indicar si es acido o bas
erastovalidia [21]

Answer:

Explanation:

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5 0
3 years ago
What do you use to find the actual amount of reactants
Rasek [7]

You need to use Stoichiometry

6 0
3 years ago
10 points. Please help.
ratelena [41]

Answer:

-191.7°C

Explanation:

P . V = n . R . T

That's the Ideal Gases Law. It can be useful to solve the question.

We replace data:

2.5 atm . 8 L = 3 mol . 0.082 L.atm/mol.K . T°

(2.5 atm . 8 L) / (3 mol . 0.082 L.atm/mol.K) = T°

T° = 81.3 K

We convert T° from K to C°

81.3K - 273 = -191.7°C

6 0
3 years ago
Read 2 more answers
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