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uranmaximum [27]
3 years ago
11

A plot of velocity versus substrate concentration for a simple enzyme-catalyzed reaction produces a _____. This indicates that a

t some point, the enzyme is _____. Group of answer choices A) straight line; inhibited by product
B) hyperbolic curve; saturated with substrate
C) sigmoidal curve; inhibited by substrate
D) hyperbolic curve; activated by substrate
E) sigmoidal curve; saturated with substrate
Chemistry
1 answer:
kirza4 [7]3 years ago
5 0

Answer:

B) hyperbolic curve; saturated with substrate

Explanation:

Enzymatic kinetics studies the speed of enzyme catalyzed reactions. These studies provide direct information about the mechanism of the catalytic reaction and the specificity of the enzyme. The speed of a reaction catalyzed by an enzyme can be measured with relative ease, since in many cases it is not necessary to purify or isolate the enzyme. The measurement is always carried out under the optimal conditions of pH, temperature, presence of cofactors, etc., and saturating substrate concentrations are used. Under these conditions, the reaction rate observed is the maximum speed (Vmax). The speed can be determined either by measuring the appearance of the products or the disappearance of the reagents.

Following the rate of appearance of product (or disappearance of the substrate) as a function of time, the so-called reaction progress curve is obtained, or simply, the reaction kinetics. This curve is represented by a hyperbolic curve

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2 years ago
What is the percent by mass of water in Na S04.10H20?
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Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

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Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

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Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

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Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

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