Answer:
<h2>23.33 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>23.33 g/mL</h3>
Hope this helps you
The atomic mass of an atom if its mass is approximately equal to carbon-12 will be 12 and in case of 4.5 times carbon-12 will be 54
Atomic mass of an element is the average mass of the atoms of an element which are measured in atomic mass unit. Or we can also say that the atomic mass is actually the weighted mass is a weighted average of all of the isotopes of elements, in which the mass of each element is multiplied by the abundance of that particular isotope.
So the atomic mass of an atom if the mass is approximately equal to carbon-12 then the mass of the element will be equal to 12 as the atomic mass of carbon-12 is 12.
where as the atomic mass of an atom if its mass is approximately equal to 4.5 times as much as carbon-12 will be ⇒ 4.5×12= 54
To know more about atomic mass
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m = 7.84x107/(3x108)2kg = 7.84x107/9x1016kg = 0.871x10-9 kg = 8.71x10-10 kg
<span>Answer: 0.00 meters
Solution:
Step 1: Define displacement
DISPLACEMENT = a vector quantity that describes "linear or angular distance in a given direction between a body or point and a reference position."
Step 2: Understand the question
Assumption 1: Assume that when the ant moves 4.25 meters from its origin to its nest, it is moving in a positive direction (on a graph you would draw a line along the x-axis from its origin to +4.25).
Assumption 2: Assume that when the ant "turns around...back to the source of food", it is moving back in the negative direction (towards the origin).
Step 3: Analyze the question
What is the distance between where the ant originally started and where it ended its journey?
The ant started and ended its journey in the same place.
While it traveled a distance of 8.52 meters (2 * 4.26 = 8.52), it's displacement is actually 0.00 meters (4.26 + (-4.26) = 0.00)
Therefore, the answer is 0.00 meters</span>
Answer:
D. Scientific notation is a way of writing large and small numbers