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3 years ago

Which of the following is equivalent to 2,100 grams?

2 answers:

6 0

<span>D is the correct answer. 10 decigrams are equivalent to 1 gram, so 2,100 grams are equivalent to 2100 x 10. This makes 21,000. </span>

Reptile [31]3 years ago

6 0

21,000 decigrams is was hard for me too. ha ha ha

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A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is

Umnica [9.8K]

The frequency of note C3 is 131 $s^{-1}$ .

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

$Frequency=\frac{speed of sound}{Wavelength of note}$

Thus,

$Frequency = \frac{343 m/s}{2.62 m} = 131 s^{-1}$

So the frequency of note C3 is 131 $s^{-1}$ .

3 0

3 years ago

What is the period of an objects motion?

Lyrx [107]

The time for an object to complete one full cycle. Can have a long period or short period.

Brainliest?

8 0

3 years ago

I NEED MAJOR HELP ON THIS AS WELL PLEASE SOMEONE HELP ME

yuradex [85]

Answer:

The total distance is 130.2 [m]

Explanation:

In order to solve this problem we must use the expressions of kinematics. The clue to solve this problem is that the cart starts from rest, i.e. its initial speed is zero.

$v_{f} =v_{o} +(a*t)$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

a = acceleration = 3 [m/s²]

t = time = 8[s]

Vf = 0 + (3*8)

Vf = 24 [m/s]

With this velocity we can calculate the displacement using the following expression.

$v_{f} ^{2} =v_{o} ^{2} +2*a*x$

where

x = distance traveled [m]

24² = 0 + (2*3*x)

x = 576/(6)

x = 96 [m]

Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.

The other important clue to solve this problem in the second part is that the final velocity is now the initial velocity.

We must calculate the final velocity.

$v_{f}= v_{i} -(a*t)$

Vf = final velocity [m/s]

Vi = initial velocity = 24 [m/s]

a = desacceleration = 1.6 [m/s²]

t = time = 15 [s]

Vf = 24 - (1.6*15)

Vf = 21.6 [m/s]

With this velocity, we can calculate the displacement using the following expression.

$v_{f} ^{2} =v_{o} ^{2} -2*a*x$

where

x = distance traveled [m]

21.6² = 24² - (2*1.6*x)

x = 109.44/(3.2)

x = 34.2 [m]

Note: The negative sign in the equations is because the car is desaccelerating, it means its velocity is decreasing.

Therefore the total distance is Xt = 34.2 + 96 = 130.2 [m].

5 0

3 years ago

Two children of mass 20 kg and 30 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c

Fiesta28 [93]

Answer:

Explanation:

Given

mass of first child $m_1=20\ kg$

mass of second child $m_2=30\ kg$

Distance between two children is $d=3\ m$

Suppose light weight child is placed at a distance of x m from Pivot point

therefore

Torque due to heavy child $T_1=m_2g\times (3-x)$

Torque due to small child $T_2=m_1g\times x$

Net Torque about Pivot must be zero

Therefore $T_1=T_2$

$30\times g\times (3-x)=20\times g\times x$

$9-3x=2x$

$9=5x$

$x=\frac{9}{5}$

$x=1.8\ m$

7 0

3 years ago

A snail can crawl 160cm at an avg speed of 4cm/min. If it crawled at an avg speed of 5cm/min instead, how much sooner would it t

mihalych1998 [28]

Answer:

8 minutes sooner

Explanation:

Average speed of snail= 4cm/min

Distance to be covered = 160cm

Time taken for the journey = distance/speed

Time taken for the journey = 160/4

Time taken for the journey = 40 min

If it crawed an average speed of 5cm/min

Distance = 160 cm

Time for the journey = distance/speed

Time for the journey = 160/5

Time for the journey = 32 min

Its going to take the snail 40 min - 32 min to Kno how sooner it will taje it if the average speed is 5cm/min

40 min - 32 min = 8 min

7 0

4 years ago