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solmaris [256]
3 years ago
7

Which of the following is equivalent to 2,100 grams?

Physics
2 answers:
kupik [55]3 years ago
6 0
<span>D is the correct answer. 10 decigrams are equivalent to 1 gram, so 2,100 grams are equivalent to 2100 x 10. This makes 21,000. </span>
Reptile [31]3 years ago
6 0

21,000 decigrams  is was hard for me too. ha ha ha


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A small grinding wheel is attached to the shaft of an electric motor which has a rated speed of 3600 rpm. When the power is turn
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Answer:

(a) θ1 = 942.5rad, (b) θ2 = 13195 rad

Explanation:

(a) Given

ωo = 0 rad/s

ω = 3600rev/min = 3600×2(pi)/60 rad/s

ω = 377rad/s

t1 = 5s

θ1 = (ω + ωo)t/2

θ1 = (377 +0)×5/2

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(b) ωo = 377rad/s

ω = 0 rad/s

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3 years ago
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Vi = vf + ( a.t)
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2 years ago
A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

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We need to calculate the pressure of the remaining gas

Using equation of ideal gas

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V = volume

T = temperature

Put the value in the equation

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When the temperature of the gas is increased

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Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

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