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Kay [80]
3 years ago
5

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an

swer as an angle between 0∘ and 360∘. Express your answer in degrees.
Physics
1 answer:
AveGali [126]3 years ago
6 0

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

\phi=123.75

Explanation:

From the question we are told that:

Height h=27m

Period T=32sec

Time t=75sec

Generally the equation for angular velocity is mathematically given by

\omega=\frac{2 \pi}{T}

\omega=\frac{2 \pi}{32}

\omega=0.196rad/s

Therefore

\theta=\omega t

\theta=0.196rad/s*75sec

\theta=843.75 \textdegree

Therefore

\phi=\theta-2(360)

\phi=123.75

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5 0
2 years ago
The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second
just olya [345]

Answer:

g=274\ m/s^2

Explanation:

Mass of the Sun, M=1.99\times 10^{30}\ kg

The radius of the Sun, r=6.96\times 10^8\ m

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2

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