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Kay [80]
3 years ago
5

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an

swer as an angle between 0∘ and 360∘. Express your answer in degrees.
Physics
1 answer:
AveGali [126]3 years ago
6 0

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

\phi=123.75

Explanation:

From the question we are told that:

Height h=27m

Period T=32sec

Time t=75sec

Generally the equation for angular velocity is mathematically given by

\omega=\frac{2 \pi}{T}

\omega=\frac{2 \pi}{32}

\omega=0.196rad/s

Therefore

\theta=\omega t

\theta=0.196rad/s*75sec

\theta=843.75 \textdegree

Therefore

\phi=\theta-2(360)

\phi=123.75

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Answer:

0.00712 m

Explanation:

Given:

Charge on first particle (q₁) = 75 nC = 75\times 10^{-9}\ C

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Force (F) = 1.00 N

Separation (d) = ?

The magnitude of force is given by Coulomb's law which states that, the magnitude of force acting between two charged particles separated by a distance is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

Therefore, the magnitude of force is given as:

F=\dfrac{k|q_1||q_2|}{d^2}

Where, k=9\times 10^9\ N\cdot m^2/ C^2 is the coulomb's constant.

Plug in the given values and solve for 'd'. This gives,

1.00=\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{d^2}\\\\d^2=\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{1.00}\\\\d=\sqrt{\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{1.00}}\\\\d=0.00712\ m

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<span> False. A Red Giant evolves from a main sequence star after it commences Helium fusion and undergoes a great expansion; in the case of our Sun it would expand to encompass Earth's orbit. Thus, it would have approximately the same mass (a small amount being expelled in the helium flash), and vastly greater volume, equating to vastly lower density.

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How is carbonic acid responsible for the formation of some caves? ASAP PLEASE!!!!
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3 years ago
A proton that has a mass m and is moving at +164 m/s undergoes a head-on elastic collision with a stationary carbon nucleus of m
Irina18 [472]
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:

m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,

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30x30=900

The answer is 900 meters after 30 seconds

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