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Troyanec [42]
3 years ago
8

PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

Its right you dont have to change anything

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How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
dezoksy [38]

Answer:

1.40 atm is the pressure for the gas

Explanation:

An easy problem to solve with the Ideal Gases Law:

P . V = n . R .T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm

7 0
3 years ago
Read 2 more answers
If the heat of reaction is negative, that means that:
Crazy boy [7]

Answer:

if the heat of reaction is positive, the reaction is said to be endothermic; if negative, exothermic.

Explanation:

hope this helps

i am so sorry if this is the wrong answer

4 0
2 years ago
7. What is the voltage when the resistance is 6 ohms and the current is 8 amps?
vivado [14]

Answer:

48 volts

Explanation:

Voltage (E) = Current (I) x Resistance (R), or E = IR.

4 0
3 years ago
Read 2 more answers
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
3 years ago
How much work does a gas do when it expands against a constant pressure of 0.600 atm from a volume of 50.00 mL to a volume of 44
miskamm [114]

Answer:

23.71J is the work that the gas do.

Explanation:

The work that a gas do under isobaric conditions follows the formula:

W = P*ΔV

<em>Where W is work in atmL, P is the pressure and ΔV is final volume -Initial volume In Liters</em>

Replacing with the values of the problem:

W = P*ΔV

W = 0.600atm*(0.44000L - 0.0500L)

W = 0.234atmL

In Joules (1atmL = 101.325J):

0.234atmL × (101.325J / 1 atmL) =

<h3>23.71J is the work that the gas do.</h3>

<em />

3 0
3 years ago
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