1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Galina-37 [17]
3 years ago
6

What are 3 elements similar to silver

Chemistry
2 answers:
Ainat [17]3 years ago
7 0

Answer:

Copper, Sodium, and Francium

Explanation:

sesenic [268]3 years ago
3 0
Are there any options?
You might be interested in
Mason notices that his boat sinks lower in the water in a freshwater lake than in the ocean. what could explain this
tino4ka555 [31]

Answer:

Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain this?

Explanation:

The freshwater has less density then the ocean!

6 0
3 years ago
Which of the following best describes how electrically charged
OleMash [197]

Answer:

As electric current flows through a wire, it generates a magnetic field in the area surrounding the wire.

Explanation:

hope this helps

6 0
2 years ago
Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

H_2(g)+I_2(g)\rightarrow 2HI(g)

According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
3 years ago
El jueves Santo celebramos la​
ikadub [295]
Sí :))))))))))))))))))
8 0
3 years ago
A sample that is 74.5 percent chloride by mass is dissolved in water and treated with an excess of
12345 [234]

Answer:

Total mass of original sample = 0.38 g

Explanation:

Percentage of chloride = 74.5%

Mass of AgCl  precipitate = 1.115 g

Mass of original sample = ?

Solution:

Mass of chloride:

1.115 g/ 143.3 g/mol × 35.5 g/mol

0.0078 g × 35.5 = 0.28 g

Total mass of compound:

Total mass = mass of chloride / %of Cl × 100%

Total mass = 0.28 g/ 74.5% × 100%

Total mass = 0.0038 g× 100

Total mass = 0.38 g

5 0
3 years ago
Other questions:
  • What statement would beast describe a digital signal
    15·1 answer
  • What are two things with the same volume but different masses?
    7·1 answer
  • Neon belongs to what family
    12·1 answer
  • What reagent is <br>used to test for starch<br>​
    8·1 answer
  • The chemical formula for aluminum + oxygen
    7·1 answer
  • I set up the conversion factor as 1 mol H20 / 18.02 g H2O because?
    6·1 answer
  • Where do reactions in a solid
    9·1 answer
  • 2. The air pressure inside a submarine is 0.56 atm. What would be the pressure in<br> mmHg?
    8·1 answer
  • Calcule la formula empírica de la sustancia está compuesta por 18,4% de carbono 21,5% de nitrógeno y 60,1% de potasio
    11·1 answer
  • What happens to the ionizing rate if the steps of ionizing polyprotic acid increases?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!