When 100 mL of 1.0 M Na3PO4 is mixed with 100 mL of 1.0 M AgNO3, a yellow precipitate forms and [Ag ] becomes negligibly small.
Which of the following is a correct listing of the ions remaining in solution in order of increasing concentration? a. PO43- < NO3- < Na+
b. PO43- < Na+ < NO3-
c. NO3- < PO43- < Na+
d. Na+ < NO3- < PO43-
e. Na+ < PO43- < NO3-
In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M
The answer is A) PO43- < NO3- < Na+
Explanation:
Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-
We have 100mL of each reactant with the same concentration for both (1.0 M) so:
Explanation:In a solid, the atoms are closely packed and hence are close together. This results in a definite pattern of packing and a definite shape. Solids have a defined shape and volume as a result of this orderly arrangement of atoms very close to each other in the solid material.
