Hello! Your question seems incomplete, still I will try to answer it in a general way. As shown in in equation 22 KJ heat is absorbed during the reaction so it is endothermic reaction.
Effect of Temperature:
According to Le Chatelier's principle, by increasing temperature the equilibrium will shift in the forward direction hence more nitrogen and hydrogen will produce.
Effect of Pressure:
It is evident from the reaction that there is an increase in volume in the formation of N2 and H2 (4 moles in whole), Hence, decrease in pressure on this system in equilibrium state will adjust itself in a direction in which the volume is increased i.e. formation of N2 and H2.
Effect of Concentration:
Increasing concentration of NH3, removal of N2 or removal of H2 will shift the equilibrium in forward direction, Hence more product is formed.
Lead can be extremely poisonous and was once used in many many paints but caused several deaths from lead poisoning so that was a biggie...
At the center of every chlorophyll molecule, in every plant, there is a magnesium ion. Magnesium is one of the two dozen or so elements that are <em>required </em>for life.
Sulfur reacts with oxygen to yield SO3 as shown in the equation below;
2S(g)+ 3O2(g) = 2SO3(g)
From part A 7.49 g of S were used.
The atomic mass of sulfur is 32.06 g/mol
Hence, the number of moles of sulfur used
7.49 / 32.06 = 0.2336 moles
The mole ratio of S : SO3 is 1:1
Thus the mass of SO3 will be ( 1 mol of SO3= 80.06 g)
0.2336 moles × 80.06 = 18.7 g
Answer:
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Explanation:
Step 1: Data given
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L
Temperature = 198 °C = 471 K
The volume will be reduced to 2.50 L
Step 2 Calculate the new temperature via Charles' law
V1/T2 = V2/T2
⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L
⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K
⇒with V2 = the reduced volume of the gas = 2.50 L
⇒with T2 = the new temperature = TO BE DETERMINED
5.10 L / 471 K = 2.50 L / T2
T2 = 2.50 L / (5.10 L / 471 K)
T2 = 230.9 K = -42.1
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
