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Inessa05 [86]
3 years ago
9

what's the main difference between continuous compounding and exponential growth, and why does my text book say that it is bette

r to express growth rates as if they are continuously compounded? What's the advantage---both give outrageous estimates to "what if" scenarios. ...?
Chemistry
1 answer:
Annette [7]3 years ago
4 0
The big advantage to using continuous compounding to express growth rates is it avoids the problem of asymmetry in growth rates:

For example, if we use the normal definition and $100 grows to $105 in one time period, that's a growth rate of $105/$100 - 1 = 5% But if $105 decreases to $100, that's a growth rate of $100/$105 - 1 = -4.76%

The problem of asymmetry is those two growth rates, 5% and -4.75% are not equal up to a sign.

But if you use continuous compounding the growth rate in the first case is ln(105/100) = 0.04879.
And the growth rate in the second is ln (100/105) = -0.04879.
Those two growth rates are definitely the negative of each other.<span>
</span>
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Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that
Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

<u />

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

<u />

See figure 1 to further explanations.

I hope it helps!

<u />

<u />

8 0
3 years ago
What is the organic product formed when ethanoic acid reacts with ethanol?​
Nutka1998 [239]

Answer:

Ethyl ethanoate is formed

5 0
3 years ago
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of
lianna [129]

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2     (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

8 0
4 years ago
Find the oxidation number of hydrogen in HNC. ​
dem82 [27]
The oxidation number of hydrogen in HNC is +1.

In fact, the oxidation number of hydrogen in any compound will generally be +1; a major exception would be in the case of metal hydrides (e.g., NaH), where the hydrogen exists as a negative ion.
8 0
3 years ago
Read 2 more answers
When (1R,2R)-1-chloro-2-methylcyclohexane is heated with NaOCH3, the predominant product is...?
Alika [10]

Answer: The correct answer is option E.

Explanation:

When (1R,2R)-1-chloro-2-methylcyclohexane is heated with a strong base such as NaOCH3, the predominant product will be an alkene.

It is important to note that when such compounds undergo elimination as a result of heat, the resultant product is usually an alkene.

The available options are:

A. 3-methylcyclohex-1-ene (racemic)

B. methylcyclohexene

C. (1S,2R)-1-methoxy-2-methylcyclohexane

D. (S)-3-methylcyclohex-1-ene

E. (R)-3-methylcyclohex-1-ene

F. (1R,2R)-1-methoxy-2-methylcyclohexane

The correct answer is E.

Therefore, the compound will undergo elimination reaction to give an alkene( . (R)-3-methylcyclohex-1-ene ).

8 0
4 years ago
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