Answer:
The pulling force applied to the cord connecting the larger flywheel is 30.88 N
Explanation:
Given;
the radius of the smaller flywheel, r₁ = 21 cm
force on the cord of the smaller flywheel, F₁ = 50 N
the radius of the larger flywheel, r₂ = 34 cm
The torque on each flywheel is equal, since there is no rotation.
τ = Fr
where;
τ is torque on each flywheel
F is the force on the cord of each flywheel
r is the radius of each flywheel
F₁r₁ = F₂r₂
Therefore, the pulling force applied to the cord connecting the larger flywheel is 30.88 N
Answer:
The coordinates of the point is (0,0.55).
Explanation:
Given that,
First charge at origin
Second charge
Second charge at point P = (0,1)
We assume that,
The net electric field between the charges is zero at mid point.
Using formula of electric field
Hence, The coordinates of the point is (0,0.55).
Answer:
a_total = 2 √ (α² + w⁴) , a_total = 2,236 m
Explanation:
The total acceleration of a body, if we use the Pythagorean theorem is
a_total² = a_T²2 + ²
where
the centripetal acceleration is
a_{c} = v² / r = w r²
tangential acceleration
a_T = dv / dt
angular and linear acceleration are related
a_T = α r
we substitute in the first equation
a_total = √ [(α r)² + (w r² )²]
a_total = 2 √ (α² + w⁴)
Let's find the angular velocity for t = 2 s if we start from rest wo = 0
w = w₀ + α t
w = 0 + 1.0 2
w = 2.0rad / s
we substitute
a_total = r √(1² + 2²) = r √5
a_total = r 2,236
In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m
a_total = 2,236 m