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Olenka [21]
3 years ago
7

If a trapeze artist rotates once each second while sailing through the air, and contracts to reduce her rotational inertia to on

e fourth of what it was, how many rotations per second will result?
Physics
1 answer:
finlep [7]3 years ago
4 0

Answer:

There are finally 4 rotations per second.

Explanation:

If a trapeze artist rotates once each second while sailing through the air, and contracts to reduce her rotational inertia to one fourth of what it was. We need to find the final angular velocity. It is a case of conservation of angular momentum such that :

I_1\omega_1=I_2\omega_2

Let I_1=I , I_2=\dfrac{I}{4} and \omega_1=1

So,

\omega_2=\dfrac{I_1\omega_1}{I_2}

\omega_2=\dfrac{I\times 1}{(I/4)}

\omega_2=4\ rev/sec

So, there are finally 4 rotations per second. Hence, this is the required solution.

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Answer:

The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm

Explanation:

The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:

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Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:

Fp = F*sin(a)

Replacing the values for the force and the angle:

Fp = 33N*sin(π/5)  = 33N * 0.011 = 0.363 N

Taking the distance in meters:

T = 0.2m * 0.363 N = 0.063 Nm

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