What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?
2 answers:
Answer: .
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of Na = 43.38 g
Mass of C = 11.33 g
Mass of O = 45.29 g
Step 1 : convert given masses into moles.
Moles of Na=
Moles of C =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Na =
For C =
For O =
The ratio of Na : C: O = 2: 1: 3
Hence the empirical formula is .
What is the empirical formula of a compound that contains 43.38% sodium, 11.33% carbon, and 45.29% oxygen?
Na2CO3
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