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melisa1 [442]
3 years ago
5

What is the total number of electrons shared in a double covalent bond?

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
3 0
The correct answer is option 4. In a double covalent bond, two pairs of electrons are bonded or there is a total of four electrons being shared in a bond. For example, we have oxygen. Two atoms of oxygen share two pairs of electrons to have a stable structure.
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What is the satndard used in any measurment
amid [387]
It is expressed in inches,feet,and pounds, centimeters,meters and kilograms in the metric system.(I hope this helps)
7 0
3 years ago
If you start with 5 molecules of O2 in the reaction 2Mg + O2 2 MgO, how much Mg will you need
hichkok12 [17]
2Mg + O₂ ---> 2MgO

2 atoms Mg --- 1 molecules O₂
X atoms Mg --- 5 molecules O₂
X = 2×5
X = 10 atoms Mg
4 0
3 years ago
The molar solubility if Pb(IO3)2 in
lana66690 [7]

Answer:

Ksp = 2.4 * 10^-13

Explanation:

Step 1: Data given

Molarity of NaIO3 = 0.10 M

The molar solubility of Pb(IO3)2 = 2.4 * 10^-11 mol/L

Step 2: The initial concentration

NaIO3 = 0.1M

Na+ = 0 M

2IO3- = 0 M

Step 3: The concentration at the equilibrium

All of the NaIO3 will react (0.1M)

At the equilibrium the concentration of NaIO3 = 0 M

The mol ratio is 1:1:1

The concentration of Na+ and IO3- is 0.1 M

Pb(IO3)2 → Pb^2+ + 2IO3^-

The concentration of Pb(IO3)2 can be written as X

The concentration of Pb^2+ can be written as X

The concentration of 2IO3^- can be written as 2X

Ksp = (Pb^2+)(IO3^-)²

⇒ with (Pb^2+) = 2.4*10^-11

 ⇒ with (IO3^-) = 2x from the Pb(IO3)2 and 0.1M from the NaIO3.

   ⇒The total (IO3^-) = 2x + 0.1 and we assume that x is so small that we can neglect it.

Ksp = (2.4 *10^-11)*(0.1)²

Ksp = 2.4 * 10^-13

7 0
3 years ago
An liquid's mass is 79.6 g. A student measures the volume to be 42.5mL. What is the density of the liquid?
morpeh [17]

Answer:

The answer is

<h2>1.87 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of liquid = 79.6 g

volume = 42.5 mL

The density of the liquid is

density =  \frac{79.6}{42.5}  \\  = 1.87294117...

We have the final answer as

1.87 g/mL

Hope this helps you

4 0
3 years ago
Help anyone can help me do this question,I will mark brainlest.​
Vika [28.1K]

Explanation:

NA2SO3

Combination of these three elements forms following compounds.

And the compound that's going to be formed,depends on the ratio of available oxygen and sulphur.

Depends on the ratio of sulfur to oxygen...

sodium sulfate, Na2SO4

sodium sulfite, Na2SO3

sodium thiosulfate, Na2S2O3

ionic bond is present in between SO3 -2 and Na+2

structure of SO3 -2 [take - sign as delta - which here indicates,partial formal charge of oxygen] (image below)

Here,The oxygen is more electronegative.So,2 oxygen atoms drag one Electron from sulphur atom,leaving behind the formal charge of -1 on two oxygen atoms.

The third oxygen forms covalent bond by sharing 2 electrons. (Actually this ion has resonance structure)

This sulphite ion combines with two sodium ions to form two ionic bonds.This happens when sodium, being an alkali metal dontes it's valence electron to oxygen.

SO2

In Sulphur dioxide, Sulphur is bonded to 2 oxygen atoms. Oxygen is more electronegative than Sulphur and thus, shows a fixed valency of 2. As a result each oxygen forms two bonds with the Sulphur atom making its valency 4.

NAHSO4

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Questions & Answers

CBSE

Chemistry

Grade 11

Oxidation State or Oxidation Number

Question

Answers

Related Questions

The oxidation state of sulphur in NaHSO4 ?

A) 0

B) + 2

C) −2

D) + 4

E) + 6

Answer

VerifiedVerified

72.9K+ Views

Hint: The oxidation state is defined as the charge on the atom. The sum of the oxidation state of an atom in a molecule is equal to the charge on the molecule. The neutral molecules charge less species. It has zero charges.

Complete Solution :

- The oxidation number of an atom is defined as the charge on an atom that appears on the atom on forming an ionic bond. An atom which has higher electronegativity has a negative oxidation state and more electropositive elements have positive oxidation state.

- We are interested in determining the oxidation state of an atom in a molecule. We know that the net charge on a neutral atom or molecule is always equal to zero. Let’s determine the oxidation state of S in the NaHSO4 .

- The oxidation number of alkali metal that is a sodium atom is equal to +1 . Similarly the hydrogen has an +1 oxidation state. Oxygen is an electronegative element. It has an −2 oxidation state. The oxidation states are as listed below:

Element Oxidation state

Na +1

H +1

O −2

We know that the sum of the oxidation state of an atom in a neutral molecule is equal to zero. Then we have,

0 = O.S. of Na + O.S. of H + O.S. of S + 4(O.S. of O)

Let’s substitute the values of oxidation state .we have,

0 = 1 + 1 + O.S. of S + 4(−2)⇒O.S. of S= 8−2 = +6

Therefore the oxidation state of sulphur in NaHSO4 is equal to +6 . So, the correct answer is “Option E”.

H2S

Valency of sulphur is 2 in H2S

5 0
3 years ago
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