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nlexa [21]
4 years ago
14

A computer has a CPU that can execute 10 million instructions per second and a memory has a transfer rate of 100 million bytes p

er second. When interrupt-driven I/O is performed, the ISR has to execute 50 instructions to transfer one byte between memory and I/O device. What is the maximum data transfer rate during I/O operations implemented by using interrupt-driven I/O
Computers and Technology
1 answer:
asambeis [7]4 years ago
8 0

Answer:

2 x 10⁵ bytes per second

Explanation:

Given:

MIPS rate = maximum speed of CPU to execute instructions = 10 million instructions per seconds

number of instructions required to transfer 1 byte using interrupt driven I/O = 50

Maximum number of bytes that can be transferred in 1 second = MIPS rate / number of instructions for 1 byte

=> max number of bytes = 10 million / 50 = 10 x 10⁶ / 50 = 2 x 10⁵

which is less than the maximum transfer rate of memory = 100 million bytes per second

So, maximum data transfer rate during I/O operations by using interrupt-driven I/O is 2 x 10⁵ bytes per second

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Answer:

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Explanation:

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4 years ago
Write a program that declares an array named myArray with 8 components of the type int. Initialize the array to 8 values that th
Savatey [412]

Answer:

#include <iostream>

using namespace std;

void filterEvens(int myArray[]) {

   for (int i = 0; i < 8; ++i) {

     if(myArray[i]%2==0){

         cout<<myArray[i]<<" ";

     }

  }

}

int main(){

   int myArray[8];

   for(int i =0;i<8;i++){

       cin>>myArray[i];

   }

   filterEvens(myArray);

   return 0;

}

Explanation:

The solution is provided in C++

#include <iostream>

using namespace std;

The function filerEvens is defined here

void filterEvens(int myArray[]) {

This iterates through the elements of the array

   for (int i = 0; i < 8; ++i) {

This checks if current element is an even number

     if(myArray[i]%2==0){

If yes, this prints the array element

         cout<<myArray[i]<<" ";

     }

  }

}

The main begins here

int main(){

This declares an integer array of 8 elements

   int myArray[8];

The following iteration allows input into the array

<em>    for(int i =0;i<8;i++){</em>

<em>        cin>>myArray[i];</em>

<em>    }</em>

This calls the defined function filter Evens

   filterEvens(myArray);

   return 0;

}

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3 years ago
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Read 2 more answers
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Answer:

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Answer:

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