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azamat
3 years ago
14

Jessica wrote the numbers 4 1/5,3 1/3, 5 1/2 in the form of a fraction.Whats the greatest numerator that Jessica wrote?

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0
The correct answer is 5 1/2 because if it weren’t simplified it would be 6/2 which makes the numerator the greatest.
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Whats 109 divided by 27 and then simplify it
ioda

109/27 = 4.037037037

Uncertain on what exactly they want on simplified, here are a couple

Rounded (Hundredth) = 4.04

Rounded (Whole & tenth) = 4

8 0
4 years ago
I need help with this please help it’s due tonight
aivan3 [116]

Answer:

OZQ=125°

OZP=62°

PZQ=OZQ+OZP

PZQ=125+62

PZQ=187°

6 0
3 years ago
Find the probability that the person is frequently or occasionally involved in charity work.
Schach [20]
Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

\begin{tabular}
{|c|c|c|c|c|c|}
 &Frequently&Occassionally&Not at all&Total\\[1ex]
Male&227&454&798&1,479\\
Female &205&450&747&1,402\\
Total&432&904&1,545&2,881
\end{tabular}

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}



Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

P(being
 \ female \ or \ not \ being \ involved)\\ \\= 
\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = 
\frac{2200}{2881}=\bold{0.764}



Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

P(being
 \ male \ or \ being \ frequently \ involved)\\ \\= 
\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = 
\frac{1684}{2881}=\bold{0.585}



Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

P(being
 \ female \ or \ not \ being \ frequently \ involved)\\ \\= 
\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = 
\frac{2654}{2881}=\bold{0.921}



Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
4 0
3 years ago
Find UW.<br><br>(Please explain how you got UW so I know how to do the other ones!)
Aleonysh [2.5K]

Answer:

X = 6

Step-by-step explanation:

DU = DU .....(1)

DV =DW ......(2)

angle VDU = angle WDU .......(3)

so triangle VDU and triangle WDU are Congruent Triangles

thus VU = WU

we solve : 9x + 1 = 7x + 13 , x = 6

7 0
3 years ago
Please help me I don’t know
Verizon [17]

Answer: A


Step-by-step explanation: Domain is the input, or x values. You can see the points (1, 6), (2,3), (3,1), and (6,5). In ordered pairs, the x values are the numbers on the left:

(x, y)

So if we take all the numbers on the left, we get 1, 2, 3, and 6. Thus, our domain is {1,2,3,6}


8 0
3 years ago
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