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likoan [24]
3 years ago
5

Teams A and B are in a tug-of-war challenge. Team A wins the challenge.

Physics
2 answers:
xeze [42]3 years ago
8 0

Answer:

A the force was in their direction

EastWind [94]3 years ago
4 0

Answer:

A. The net force was in their direction.

Explanation:

In the game of tug of war the two teams will pull the two ends of the rope with different forces.

When the two teams will pull the two ends of the rope then the team who win is the one who pull the rope towards them.

so here in order to win Team A we know that team A has to pull the rope towards them.

So it must have more force towards them.

So net force is always towards team A in order to win the game

So here correct answer will be

A. The net force was in their direction.

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A proton that has a mass m and is moving at +164 m/s undergoes a head-on elastic collision with a stationary carbon nucleus of m
Irina18 [472]
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:

m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,

m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂'  --> equation 1

The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is

(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2

Solving equations 1 and 2 simultaneously, v₁' =  -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
7 0
3 years ago
You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of
Rzqust [24]

Answer:

<h2>3.36J</h2>

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

                                       = 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0
2 years ago
How many dots belong in the electron dot diagram of a boron(B) atom
sergij07 [2.7K]
three dots belong in the electron dot diagram of a boron(B) atom.
6 0
3 years ago
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What are some examples of aerobic exercise?
Firdavs [7]

Answer:

swimming, cycling, and jogging

Explanation:

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3 years ago
Wavelength of 125 meters is moving at a speed of 10 m/s.<br> What is it's frequency?
Alexandra [31]

Answer:

Frequency= 12.5

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5 0
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