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3 years ago

Teams A and B are in a tug-of-war challenge. Team A wins the challenge.

Physics

2 answers:

xeze [42]3 years ago

8 0

Answer:

A the force was in their direction

EastWind [94]3 years ago

4 0

Answer:

A. The net force was in their direction.

Explanation:

In the game of tug of war the two teams will pull the two ends of the rope with different forces.

When the two teams will pull the two ends of the rope then the team who win is the one who pull the rope towards them.

so here in order to win Team A we know that team A has to pull the rope towards them.

So it must have more force towards them.

So net force is always towards team A in order to win the game

So here correct answer will be

A. The net force was in their direction.

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Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente

yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

$v=\lambda f$ (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

$\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m$

hence, the wavelength of the wave is 28,14 m

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3 years ago

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Vanyuwa [196]

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3 years ago

Factor the expression 27x-18y

Eva8 [605]

Answer:

9(3x-2y)

Explanation:

27x-18y, the common factor here is 9

9(3x-2y)

7 0

3 years ago

A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her

lisabon 2012 [21]

Answer:

10.09 N

Explanation:

Analogously to Newton's second law, torque can be defined as:

$\tau=I\alpha$

Here, I is the moment of inertia and $\alpha$ is the angular acceleration. We have:

$\tau=(0.65kg*m^2)(29.5\frac{rad}{s^2})\\\tau=19.18N*m$

Torque is the vector product of the position vector of the point at which the force is applied by the force vector:

$\vec{\tau}=\vec{r}\times \vec{F}$

Since the effective lever arm is perpendicular to the force, the angle between them is $90^\circ$ . The magnitud of this vector product is defined as:

$\tau=rFsen\theta$ .

Solving for F and replacing the known values:

$F=\frac{\tau}{rsen\theta}\\F=\frac{19.18N*m}{1.9m(sen90^\circ)}\\F=10.09N$

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3 years ago

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Shalnov [3]

Lighting gives a sense of scale (The sky)

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3 years ago