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DIA [1.3K]
3 years ago
14

Only 11% of all the energy used in the US comes from a renewable source. Why is this a problem?

Chemistry
1 answer:
mr Goodwill [35]3 years ago
5 0
Fossil fuels and unnatural energy sources still dominate in the US, this influences many problems including global warming, climate change, and pollution. Burning fossil fuels is also a problem to human health. And unnatural resources won’t be there forever whereas, renewable sources could last a long time.
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Butane is also a molecular compound. what is its formula? how many atoms does it contain?
pishuonlain [190]
The formula of butane is C4H10 but I don't how many atoms it contains though
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4 years ago
Convert 22.4 kg/L to kg/mL
liberstina [14]
1 kg/L -------------- 0.001 kg/mL
22.4 kg/L --------- ??

22.4 x 0.001 / 1 => 0.0224 kg/mL
7 0
3 years ago
PLEASE HELP ME!!! I WILL GIVE BRAINLIEST!!
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3 years ago
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Two reasons that a plant from a rain forest would not survive in a desert home?
ss7ja [257]

Answer: A planet from a rain forest would not survive in a desert home, for the fact they depend on water and as these live from water, without it, this leads to dehydration and with loss of water with plants, nothing is able to survive when it comes to a rain forest plant being in a desert home. Another reason is the high trees and leaves that are providing the plants enough sunlight or shade to grow, it guarantees to help keep the temperature normal. Being in a deserted area would mean that there would be a temperature change, something the plant is not used to. Without that needed shade and avoiding the scorching sun, they will die out from how different the temperature is, and how hot it is.

Explanation: I hope this helped you.

4 0
3 years ago
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What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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