Option B. <span>Rb2O + Cu(C2H3O2)2 → 2RbC2H3O2 + CuO is the correct answer. HOPE IT HELPS</span>
Wood because it doesn't belong there
To get the volume of the original solution in the dilution, we consider the dilutions that were made:
from 50 mL to 250 mL:
<span>1/5 of original was present</span>
<span>from 20 mL of 250 mL:</span>
<span>1/12.5 of the diluted mixture was presetn</span>
<span>So, V=50 mL*(1/5)*(1/12.5)= 0.8 mL of original bleaching solution was present in dilution</span>
Answer:The thing to remember about a solution's molarity is that you can express it as a fraction that has 1 L of solution as the denominator. In your case, a 2.0-M potassium chloride solution contains 2.0 moles
Explanation:The thing to remember about a solution's molarity is that you can express it as a fraction that has 1 L of solution as the denominator. In your case, a 2.0-M potassium chloride solution contains 2.0 moles
