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zloy xaker [14]
3 years ago
12

Which of the following would illustrate a quadratic relation between the dependent and independent variables when graphed?

Physics
1 answer:
Kitty [74]3 years ago
3 0

Answer: option A. a graph of the area of a circle vs. its radius r (A = πr²).



Explanation:



A quadratic relation between the dependent and independent variables shows the independent variable raised to the power of 2.



This is it is a polynomial with general form ax² + bx + c, whewre a, b, and c, named coeficients,  are constants.



The function is y =  ax² + bx + c, where x is the independent variable and y is the dependent variable.



As stated in the question, the area of a circle is given by A = πr².



In this case, A is the dependent variable and r is the independent variable.



π is assumed as the coefficient of the quadratic term, and the other coefficients are assumed 0, since there are no either terms on r or constants.



The equation a = 1/b  is an inverse relation, not a quadratic relation.



The relation of distance vs. time for a car moving at constant speed is a linear relation of the kind v = u + st.



The mass of water vs. the volume of water in a drinking glass is a direct relation, mass = density × volume



Therefore, the only quadratic relation is shown by  a graph of the area of a circle vs. its radius r.

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A BMX bicycle rider takes off from a ramp at a point 2.4 m above the ground. The ramp is angled at 40 degrees from the horizonta
adoni [48]

Answer:

The BMX lands 5.4 m from the end of the ramp.

Explanation:

Hi there!

The position of the BMX is given by the position vector "r":

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

r = position vector at time t

x0 = initial horizontal position

v0 = initial velocity

α = jumping angle

y0 = initial vertical position

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive)

Please, see the attached graphic for a better understanding of the situation. At final time, when the bicycle reaches the ground, the vector position will be "r final" (see figure). The y-component of the vector "r final" is - 2.4 m (placing the origin of the frame of reference at the jumping point). With that information, we can use the equation of the y-component of the vector "r" (see above) to calculate the time of flight. With that time, we can then obtain the x-component (rx in the figure) of the vector "r final". Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

-2.4 m = 0 m + 5.9 m/s · t · sin 40° - 1/2 · 9.8 m/s² · t²

0 = -4.9 m/s² · t² + 5.9 m/s · t · sin 40° + 2.4 m

Solving the quadratic equation:

t = 1.2 s

Now, we can calculate the x-component of the vector "r final" that is the horizontal distance traveled by the bicycle:

x = x0 + v0 · t · cos α

x = 0 m + 5.9 m/s · 1.2 s · cos 40°

x = 5.4 m

The BMX lands 5.4 m from the end of the ramp.

Have a nice day!

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On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass
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Answer with Explanation:

We are given that

A.Mass,m=12 kg

\theta=53^{\circ}

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Speed,v=1.5m/s

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F_{net}=0

Fsin\theta-f=0

Fsin\theta=f

Net force in y direction

N-mg-Fcos\theta=0

N=mg+Fcos\theta

f=\mu_kN=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_kmg+\mu_kFcos\theta

Fsin\theta-\mu_kFcos\theta=\mu_kmg

F(sin\theta-\mu_kcos\theta)=\mu_kmg

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Answer: Hello!

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this can be calculated as the quotient of the distance and the velocity; this is:

t = \frac{16 mi}{165 mi/h} = 0.096 h

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

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then Lewis needs 5.8 minutes in order to cover 16 miles if his speed is 156 miles per hour.

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