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Assoli18 [71]
3 years ago
5

In 10 seconds, a lion did 150 J of work moving her lion cub up a tree for safety. How much power did she use?

Physics
1 answer:
kvasek [131]3 years ago
7 0

Answer:  

15W is the power used by the lion to take cub up a tree.

<u>Explanation:</u>

In the given question it is said that the total work done by the lion is 150 joules and the required time is 10 seconds. According to mathematical formula of power, Power =\frac{\text {work done}}{\text {time}}  substitute the given terms in the formula = \frac{150}{10} =15 = 15W (Watt is the SI unit of power. Watt is said as one joule per second). The power used by a lion to safe her cub is 15W.

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The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\rm  m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

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