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liberstina [14]
3 years ago
8

239 Pu 4 He 94 2 Fill in the missing particle

Chemistry
1 answer:
lubasha [3.4K]3 years ago
7 0

Answer:

la particula que queda es h2o

Explanation:

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Which of the following are sources of revenue for media companies? A. Direct sales to producers B.advertising and subscriptions
Fed [463]

Answer:

c

Explanation:

5 0
3 years ago
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2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
(Please help!)
Inessa [10]

Answer:

B. temperature decreases as altitude increases.

Explanation:

Just like in the lower reaches of the atmosphere, the troposphere, in the mesosphere, temperature decreases as altitude increases.

The mesosphere is the third layer of the atmosphere just above the stratosphere.

  • It begins at the top of the stratosphere and ends at the mesopause where the thermosphere begins.
  • The mesosphere is often referred to as the middle layer.

With increasing height, the temperature of the mesosphere decreases significantly. The top of the mesosphere is one of the coldest part of the earth atmosphere. This is as a result of increasing atmospheric cooling by carbon dioxide in this region of the atmosphere.

7 0
3 years ago
If the mass of 3 black beans it's 0.7 what's the mass of one bean?
mamaluj [8]

Answer:0.233333333

Explanation: Let me be!

3 0
2 years ago
Read 2 more answers
If there are 80 liters of argon gas in a piston and the piston expands the gas until its volume is 2000 liters with a pressure o
Mice21 [21]

Answer: The correct answer is A. 11.5 atm. The temperature is held constant at 293 K, therefore, we can use Boyle's Law to determine the initial pressure. Boyle's Law states that there is an inverse relationship between pressure and volume of gases. Therefore, as volume increases, the pressure will decrease and vice versa.

Further Explanation:

Boyle's Law can be mathematically expressed as:

P_{initial}V_{initial}\ = P_{final}V_{final}

In this problem, we are given the values:

P(initial) = ?

V(initial) = 80 L

P (final) = 0.46 atm

V (final) = 2000 L

Plugging in these values into the equation:

P_{initial}(80 \ L) = \ (0.46 \ atm)(2000 \ L)\\P_{initial} \ = \frac{(0.46 \ atm) \ (2000 \ L)}{80 \ L}\\P_{initial}\ = 11.5 atm\\

The initial pressure was 11.5 atm. Since the volume increased or expanded, the space where the gas particles move is bigger, so the frequency of collisions with the wall of the container and with other particles are effectively decreased. This, therefore, decreases the pressure from 11.5 to 0.46 atm.

Learn More

  1. Learn about Charles' Law brainly.com/question/1421697
  2. Learn about Ideal Gas Law brainly.com/question/6534668
  3. Learn about Gay - Lusaac's Law brainly.com/question/1358307

Keywords: gas, Boyle's Law, Ideal Gas Law

7 0
3 years ago
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