239 Pu 4 He 94 2 Fill in the missing particle
1 answer:
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Answer:
The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,
Explanation:
To answer this problem we need to keep in mind the <u>definition of pH</u>:
- pH = -log [H⁺]
So now we <u>calculate [H⁺] using a pH value of 5.2 and of 5.6</u>:
- 5.2 = -log [H⁺]
-5.2 = log [H⁺]
= [H⁺]
6.31 x 10⁻⁶ M = [H⁺]
- 5.6 = -log [H⁺]
-5.6 = log [H⁺]
= [H⁺]
2.51 x 10⁻⁶ M = [H⁺]