It would be considered acid rain in the sense of dew fall
Energy is not created or destroyed due to the law of Conservation of Energy. Hope this helps!
It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.
<h3>What are active reading skills?</h3>
Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.
<h3>How to rate your reading skills?</h3>
In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:
Rate using numbers:
- Select a specific scale rating such as 1 to 5 or 1 10.
- Analyze honestly if you used this ability while reading the text.
- Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.
Rate using words:
- Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
- Analyze honestly your performance.
- Find the word that best fits it.
Learn more about rate in: brainly.com/question/2278897
Answer:
a=28600J; b=90.6 J/K; c=402 torr
Explanation:
(a) considering the data given
Vapour pressure P1 =0 at Temperature T1 = 42.43˚C,
Vapour pressure P2 = 273.15 at Temperature T2= 315.58 K)
Using the Clausius-Clapeyron Equation
ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)
In 760/140 = ΔH/8.314 J/mol/K × (1/315.58K -- 1/273.15K)
ΔH vap= +28.6 kJ/mol or 28600J
(b) using the Equation ΔG°=ΔH° - TΔS to solve forΔS.
Since ΔG at boiling point is zero,
ΔS =(ΔH°vap/Τb)
ΔS = 28600 J/315.58 K
= 90.6 J/K
(c) using ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)
ln P298 K/1 atm = 28600 J/8.314 J/mol/K × (1/298.15K - 1/315.58K)
P298 K = 0.529 atm
= 402 torr
Answer:
pH = 4.17
Explanation:
According to the molar concentration you stated, pH of the solution is: 4.17
Remember that pH = - log [H⁺]
and [H⁺] = 10^-pH
When:
pH > 7 → Basic solution
pH = 7 → Neutral solution
pH < 7 → Acid solution
