Answer:
Explanation: The lowest pressure in a laboratory is 4.0×10^-11Pa
Using Ideal gas equation
PV = nRT
P= 4.0×10^-11Pa
V= 0.020m^3
T= 20+273= 293k
n=number of moles = m/A
Where m is the number of molecules and A is the Avogradro's number=6.02×10²³/mol
R=8.314J/(mol × K)
PV= m/A(RT)
4.0×10^-11 ×0.020 = m/6.02×10²³(8.314×293)
m = 4.0×10^-11×0.020×6.02×10^23 / (8.314×293)
m = 1.98×10^8 molecules
Therefore,the number of molecules is 1.98×10^8
Answer:
Energy of photon is 34.45 ×10⁻¹⁹ J.
Explanation:
Given data:
Frequency of photon = 5.2×10¹⁵ s⁻¹
Plancks constant = 6.626×10⁻³⁴ Js
Energy of photon = ?
Solution:
Formula:
E = h.f
by putting values,
E = 6.626×10⁻³⁴ Js × 5.2×10¹⁵ s⁻¹
E = 34.45 ×10⁻¹⁹ J
Thus, energy of photon is 34.45 ×10⁻¹⁹ J.
Answer:
Es la tercera por qué cuando el material varía va cambiando de estado
Explanation:
342.3 g/mol
11 times 16
22 times 1
12 times 12
and then add them together