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3 years ago

Explain why it is important for cells to exchange materials.

Chemistry

1 answer:

Alla [95]3 years ago

6 0

Answer:

they need the exchange so they can grow, obtain energy, and get rid of waste. It also helps to mantian a balance of amterials in the cell.

Explanation:

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A substance is tested and has a pH of 7.0. How would you classify it?

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Answer:

Explanation:

The substance would be classified as neutral, so C.

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3 years ago

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A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t

slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically, Density = $\frac{mass}{volume}$

It is given that mass is 50 g and density is 0.934 $g/cm^{3}$ .

Hence, calculate the volume of methyl acetate as follows.

Density = $\frac{mass}{volume}$

0.934 $g/cm^{3}$ = $\frac{50 g}{volume}$

Volume = $53.53 cm^{3}$

or, = $53.53 ml$ (as 1 $cm^{3}$ = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is $53.53 ml$ .

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3 years ago

In a double-replacement reaction, the _____.

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In a double-replacement reaction, the _____.?

There are many more interesting things to ask about double replacement reactions than are contained in the list given here. But the only correct choice is:

C.reactants are two ionic compounds

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A sample of a compound contains 41.33 g of carbon and 8.67 g of hydrogen. The molar mass of the

mihalych1998 [28]

Answer:

C6H15

Explanation:

First, we calculate the empirical formula as follows:

C = 41.33 g

H = 8.67 g

We convert each mass value to mole by dividing each element by its molar mass (C = 12g/mol, H = 1g/mol)

C = 41.33g ÷ 12g/mol = 3.44mol

H = 8.67g ÷ 1g/mol = 8.67mol

Next, we divide each mole value by the smallest (3.44mol)

C = 3.44mol ÷ 3.44mol = 1

H = 8.67mol ÷ 3.44mol = 2.52

We multiply this ratio by 2 to get a simple whole number ratio

C = 1 × 2 = 2

H = 2.52 × 2 = 5.04

Based on this, the whole number ratio of C and H is 2:5, hence, the empirical formula is C2H5.

The molecular mass of the compound is given as 87.18 g/mol, hence, the molecular formula is calculated as follows:

(C2H5)n = 87.18

[12(2) + 1(5)]n = 87.18

[24 + 5]n = 87.18

(29)n = 87.18

n = 87.18 ÷ 29

n = 3.006

Approximately to whole number, n = 3

Hence, the molecular formula of the compound is [C2H5]3

= C6H15

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3 years ago