Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
120
Step-by-step explanation:
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Answer:
The common factors for 50,25,100 50 , 25 , 100 are −25,−5,−1,1,5,25 - 25 , - 5 , - 1 , 1 , 5 , 25
L'Shonda purchased a container of juice. 80 calories are from carbohydrates.
<u>Solution:</u>
Given that, LShonda purchased a container of juice that contains 200 calories.
The label says that 40% of the calories are from carbohydrates.
We have to find how many calories are from carbohydrates?
Now, according to the given information,
<em>Number of calories from carbohydrates = 40% of the total calories of the juice
</em>
Then, calories from carbohydrates = 40% of 200 calories
40% can be written in fraction as 
Hence, 80 calories are from carbohydrates.
