The photoelectric emission is possible if the wavelength of the incident light is less than that of yellow light
<em><u>The</u></em><em><u> </u></em><em><u>atomic</u></em><em><u> </u></em><em><u>nucleus</u></em><em><u> </u></em><em><u>consists</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>protons</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u>.</u></em>
<em><u>Additional</u></em><em><u> </u></em><em><u>information</u></em><em><u>:</u></em>
<em><u>Protons</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>positive</u></em><em><u>ly</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particl</u></em><em><u>e</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>negative</u></em><em><u>ly</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u>.</u></em>
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>:</u></em><em><u>)</u></em>
Answer:
Amy's speed is 2/3 faster than Bill's
Explanation:
can't believe you don't know how to do this.
Answer:
Explanation:
Force on the electron = q ( v x B )
q = - 1.6 x 10⁻¹⁹
v = (5.9i−6.4j)×10⁴
B = (−0.63i+0.65j)
v x B = (5.9i−6.4j)×10⁴ x (−0.63i+0.65j)
= (3.835 - 4.032 ) x 10⁴ k
= - 1970 k
Force on the electron = q ( v x B )
= - 1.6 x 10⁻¹⁹ x -1970 k
= 3.152 x 10⁻¹⁶ k
z-component of the force on the electron
Fz = 3.152 x 10⁻¹⁶ N
Answer:
The velocity is 18.68m/s
Explanation:
Bernoulli's equation is applicable for stream line flow of a fluid. The flow must be steady and uniform flow. The Bernoulli's equation between inlet and outlet is written as:
P1/pg + V1/2g + Z1 = P2/pg + V2^2 + Z2
Where V1 and V2 are velocity of fluid at point 1 and 2b. The diameter of the tank too will be larger than that of the nozzle. Hence the velocity at point 1 will be 0.V1= 0
Substituting the values in to the equation
250 ×10^3/1000g + 0/g + 2.5 = 100×10^3/1000g + V2^2/2g + 0
250 + 2.5g = 100 + V2^2/2
250 + (2.5 × 9.8) = 100 V2^2/2
250 + 23.525- 100 = V2^2/2
174.525 = V2^2/2
Cross multiply
174.525 × 2 = V2^2
V2 = 349.05
V2 = Sqrt(349.05)
V2 = 18.68m/s
