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kherson [118]
2 years ago
15

If there were no external forces acting on the two pucks, their complex motion could be described as the combination of the unif

orm linear motion of the center of mass and a uniform circular motion of the pucks about the center of mass. Describe how well your results agree with this expectation, and explain any deviations that you observe from the predicted behavior
Physics
1 answer:
mote1985 [20]2 years ago
3 0

The absence of external forces will make the pucks move in the form of a uniform circular motion.

<h3>What is a circular motion?</h3>

It should be noted that a circular motion simply means the movement of an object along the circumference of the circle.

In this case, the absence of external forces will make the pucks move in the form of a uniform circular motion.

If the friction is absent, the pucks will continue to move on the same path due to the first law of Newton and the law of conversation of energy. In this case,the results will match the predictions until there's loss in energy.

Learn more about circular motion on:

brainly.com/question/106339

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it depends upon what state they are in like in motion or res

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A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?
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Work done is the distance a force acts over.

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3 years ago
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A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an init
Ede4ka [16]

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

3 0
3 years ago
Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
Evgen [1.6K]

Answer:

Explanation:

In a L C R circuit, the average power is given by

P_{av}=V_{rms}I_{rms}Cos\phi

As given in the question

CosФ = R / Z

And we know that

V_{rms}=I_{rms}\times Z

So

P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}

P_{av}=I_{rms}^{2}\times R

6 0
3 years ago
1. Describe what is happening at point A when these 3 vectors act on point A. 2. Describe what happen to the resultant vector at
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Answer: Don't know sorry

Explanation:

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