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denis-greek [22]

2 years ago

13

How does space promote science education

1 answer:

Fittoniya [83]2 years ago

3 0

<span>NASA and the Mad Science Group of Montreal, Canada, have teamed in an effort to spark the imagination of children, encouraging more youth to pursue careers in science, technology, engineering and math. The two organizations recently signed a Space Act Agreement, officially launching the development of the Academy of Future Space Explorers.</span>

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Gravity pulls downward on a rock with a force of 800 N. If you pull upward on the rock with a force of 400 N, what is the total

wel

The answer is
a. 400 N downward

3 0

2 years ago

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Two rocks of different masses are rolling down a hill at the same speed. Which rock (small one or big one) would have more kinet

aivan3 [116]

Answer:

Kinetic energy of bigger rock will be more than that of smaller one.

Explanation:

Kinetic energy of the rock is given by,

Kinetic energy = $\frac{1}{2} m v^{2}$

As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock

Kinetic energy ∝ mass

So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.

Hence, Kinetic energy of bigger rock will be more than that of smaller one.

3 0

2 years ago

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At what time were the racers at the same position?<br> O 15<br> O 3s<br> O 5s<br> 0 4s

Jlenok [28]

The Answer is:

O 3s

Hope you got it right.

5 0

2 years ago

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You set a tuning fork into vibration at a frequency of 723 Hz and then drop it off the roof of the Physics building where the ac

zaharov [31]

Answer:

Explanation:

Given

Original Frequency $f=723\ Hz$

apparent Frequency $f'=697\ Hz$

There is change in frequency whenever source move relative to the observer.

From Doppler effect we can write as

$f'=f\cdot \frac{v-v_o}{v+v_s}$

where

$f'=$ apparent frequency

v=velocity of sound in the given media

$v_s=$ velocity of source

$v_0=$ velocity of observer

here $v_0=0$

$697=723\cdot (\frac{343-0}{343+v_s})$

$v_s=(\frac{f}{f'}-1)v$

$v_s=(\frac{723}{697}-1)\cdot 343$

$v_s=12.79\approx 12.8\ m/s$

i.e.fork acquired a velocity of $12.8 m/s$

distance traveled by fork is given by

$v^2-u^2=2as$

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v_s^2-0=2\times 9.8\times s$

$s=\frac{12.8^2}{2\times 9.8}$

$s=8.35\ m$

5 0

2 years ago

You accelerate a 0.43kg football 5m/s2. Calculate the force you applied to the football.

Elza [17]

The force applied on the football is 2.15 Newton.

Given the data in the question;

Mass of football; $m = 0.43kg$

Acceleration; $a = 5m/s^2$

Force applied; $F = \ ?$

To determine the force applied on the football, we use Newton's laws of motion:

$F = m * a$

Where m is the mass of the object and a is the acceleration.

We substitute our given values into the equation

$F = 0.43kg\ *\ 5m/s^2\\\\F = 2.15kg.m/s^2\\\\F = 2.15N$

Therefore, the force applied on the football is 2.15 Newton.

Learn more: brainly.com/question/2388393

7 0

2 years ago