Answer:
Freezing point of solution is -4.39°C
Explanation:
Freezing point depression's formula:
ΔT = Kf . m . i
ΔT = Freezing point of pure solvent - Freezing point of solution
0°C - X = 1.86°C/m . m . 2
i = Van't Hoff factor, ions dissolved in solution
MgCl₂ → Mg²⁺ + 2Cl⁻ i = 3 → 1 mol of Mg and 2 mol of chloride
Let's think the molality (mol/kg)
First of all, let's convert the mass of solvent from g to kg
100 g / 1000 = 0.1 kg
Molality (mol/kg) = 0.118 mol / 0.1 kg = 1.18 m
0°C - X = 1.86°C/m . 1.18 m . 2
X = - 4.39°C
Answer:
3.375moles of O₂
Explanation:
The reaction expression is given as;
2KClO₃ → 2KCl + 3O₂
Number of moles of KClO₃ = 2.25moles
Now;
To find the number of moles of O₂ produced we use known number of moles.
So;
2 mole of KClO₃ will produce 3 moles of O₂
2.25moles of KClO₃ will produce 
= 3.375moles of O₂
DNA A and B are probably the most closely related because cells get DNA from the parent cells therefor similar DNA comes from relatives.
Answer:
1.332 meters per second. // 2.664 meters per second.
Explanation:
the slower person moved 33.3 meters, and the faster person moved 66.6 meters.
the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds
slower person moved 33.3/25 = 1.332 meters per second.
faster person moved 66.6/25 = 2.664 meters per second.
Answer:
The answer to your question is 80.3%
Explanation:
Data
Percent by mass of F
molecules NF₃
Process
1.- Calculate the molar mass of nitrogen trifluoride
molar mass = (1 x 14) + (19 x 3)
= 14 + 57
= 71 g
2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.
71 g of NF₃ ------------------ 100%
57 g of F ------------------- x
x = (57 x 100)/71
x = 5700 / 71
x = 80.3%
3.- Conclusion
Fluorine is 80.3% by mass of the molecule NF₃
