D. With the same number of protons and different number of neutrons.
The molar concentration will be greater than 0.01 M
.
Since more of the compound was measured out than what was calculated, you can think of the solution as being 'stronger' than what it was calculated to be. Since a 'stronger' concentration results in a number that is higher, the molarity of this solution is going to be greater than 0.01 M.
For me the answer is E. It is composed of one Ru2+ ion and two F- ions.
The answer that i got was three
i redid it and got some answer like 4.62 x1014<span> Hz</span>
The oxidation half reaction of the reaction given above would be: Ca → Ca + 2e−. Oxidation is the loss of electrons of an element while its counterpart is called the reduction which gains the electrons that has been lost. Hope this answers the question.