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Komok [63]
3 years ago
13

A parcel of mass 10 kg rests on a lorry.When the lorry accelerates at 1.5 m/s^2,the parcel is just about to slide backwards. Wha

t is the co-efficient of friction between the parcel and the lorry?​
Physics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

The coefficient of static friction,  μ = 0.153

Explanation:

Given data,

The mass of the parcel, m = 20 kg

The acceleration of the lorry, a = 1.5 m/s²

The normal force acting on the parcel,

                                       f = m x g

                                         = 20 x 9.8

                                        = 196 N

The static frictional force acting on the lorry,

                                   F = 20 x 1.5

                                      = 30 N

The coefficient of static is

                     μ = F / f

                        = 30 / 196

                        = 0.153

Hence, the coefficient of static friction,  μ = 0.153

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                               y = y(0) + V_o,y*t_c - 0.5*g*t_c^2

                              0 = 0 + V_o,y*t_c - 0.5*g*t_c^2

                               V_o,y = 0.5*g*t_c

- The horizontal component of velocity V_o,x witch which velocity is thrown can be calculated using second kinematics equation of motion:

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                               x = x(0) + V_i,x*t_c

                               D = 0 + V_i,x*t_c

                               V_o,x + v_r = D/t_c

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                            tan(Q) = ( (0.5*g*t_c)/ (D/t_c - v_r) )

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6 0
3 years ago
Read 2 more answers
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