Answer:
The coefficient of static friction, μ = 0.153
Explanation:
Given data,
The mass of the parcel, m = 20 kg
The acceleration of the lorry, a = 1.5 m/s²
The normal force acting on the parcel,
f = m x g
= 20 x 9.8
= 196 N
The static frictional force acting on the lorry,
F = 20 x 1.5
= 30 N
The coefficient of static is
μ = F / f
= 30 / 196
= 0.153
Hence, the coefficient of static friction, μ = 0.153
